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Sonbull [250]
3 years ago
11

A compound with the empirical formula C2HF4 was found to have a molar mass of about 200g/mole. What is the molecular formula of

the compound?
Chemistry
1 answer:
alukav5142 [94]3 years ago
5 0

Answer:

C_4H_2F_8 is the molecular formula of the compound.

Explanation:

For determining the molecular formula, we need to determine the valency which is multiplied by each element to get the molecular formula.

The equation used to calculate the valency is :

n=\frac{\text{molecular mass}}{\text{empirical mass}}

We are given:

Mass of molecular formula = 200 g/mol

Mass of empirical formula of C_2HF_4 :

2 × 12 g/mol + 1 × 1 g/mol + 4 × 19 g/mol = 101 g/mol

Putting values in above equation, we get:

n=\frac{200 g/mol}{101 g/mol} =1.9 \approx 2

Multiplying this valency by the subscript of every element of empirical formula, we get:

C_{(2\times 2)}H_{(1\times 2)}F_{(4\times 2)}=C_4H_2F_8

C_4H_2F_8 is the molecular formula of the compound.

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Use the following equation to answer the questions below:
Gala2k [10]

Explanation:

The equation of the reaction is given as;

Be + 2HCl → BeCl2 + H2

What is the mass of beryllium required to produce 25.0g of beryllium chloride?

1 mol of Be produces 1 mol of BeCl2

Converting to mass;

Mass = Molar mass  *  Number of moles

9.01g of Be produces 79.92g of BeCl2

xg of Be produces 25g of BeCl2

Solving for x;

x = 25 * 9.01 / 79.92

x = 2.82 g

What is the mass of hydrochloric acid required to produce 25.0g of beryllium chloride? g

Converting 25.0g of beryllium chloride to moles;

Number of moles = Mass / Molar mass

Number of moles = 25 / 79.92 = 0.3128 mol

2 mol of HCl produces 1 mol of BeCl2

x mol of HCl would produce 0.3128 mol of BeCl2

solving for x;

x = 0.3128 * 2 = 0.6256 mol

Converting to mass;

Mass = 0.6256 * 36.5 = 22.83 g

What is the mass of hydrogen gas produced when 25.0g of beryllium chloride is also produced? g

25g of BeCl2 = 0.3128 mol of BeCl2

From the equation;

1 mol of H2 is produced alongside 1 mol of BeCl2

This means;

0.3128 mol of H2 would also be produced alongside 0.3128 mol of BeCl2

Mass = Number of moles * Molar mass

Mass = 0.3128mol * 2.0159 g/mol = 0.6306 g

3 0
3 years ago
What is the molecular formula of compound x?
givi [52]
Since there is one carbon with 4 Fluorines attached to it, and both compounds are no metals, we use the covalent method for naming,

Here we ignore the prefix for the first element if it is 1. Mono. Then pay attention to the second one, it would be tetra, because tetra means 4. Here there are 4 fluorines.

Drop ine and place ide

CF4 = carbon tetrafluoride.
4 0
3 years ago
You place a carrot in salt water for 24 hours. What do you observe about the carrot at the end of that time? Choose the two corr
natka813 [3]

Answer:

A & E

Explanation:

Salt water is a hypertonic solution, meaning it extracts water from whatever is placed in it. When a carrot loses water, it will most likely shrivel up and become limp.

8 0
3 years ago
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An order is given to administer methylprednisolone, an anti-inflammatory drug, by IV at a rate of 39 mg every 30 min. The IV bag
Korvikt [17]

Answer:

The Flow rate = 0.0208 mL/min

Explanation:

Data provided:

Rate of dose = 39 mg every 30 min = (39/30) mg/min  = 1.3 mg/min

also,

125mg of methylprednisolone is present in every 2 mL

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concentration = (125/2) mg/mL = 62.5 mg/mL

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The flow rate is given as:

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on substituting the respective values, we get

Flow rate = (1.3 mg/min) / (62.5mg/mL)

or

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3 years ago
58. A cylinder of a gas mixture used for calibration of blood gas analyzers in medical laboratories contains 5.0% CO2, 12.0% O2,
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<em><u>Answer and Explanation:</u></em>

Greetings!

Let's~answer~your~question!

Partial ~pressure ~of ~gas ~can ~be ~directly~ calculated ~by ~multiplying ~the~ percentage\\ of~ pressure~ of~ gases~ to ~the ~total ~pressure.

\boxed{Pgas~ = ~P~total~ * \% ~P ~of ~gas}

<em><u>For % of N2 gas: </u></em>

<em><u /></em>100\% - (5\% + 12\%) = 83\% ~N2<em><u /></em>

<em><u /></em>

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<em><u /></em>PO_2 ~= ~146~ atm~ *~ 0.12~ = 17.52 ~atm<em><u /></em>

<em><u /></em>~PCO_2~ = ~146~ atm ~* 0.05 = 7.3 ~atm<em><u /></em>

3 0
3 years ago
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