Answer:
bromine is more reactive non-metal.
Explanation:
Both the elements have to gain 1 electron but the size of bromine is less than the size of astatine. And therefore, the tendency of accepting an electron by bromine is more than the tendency of astatine. Hence, bromine is more reactive non-metal.
The answer is B
Explanation: Not D because only engineering does that
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I only knwi one way which is if water evaporates from a mixture
The elements should be label as follows yellow = OH, blue = Fe, green = Ba, red = Cl
The mix between aqueous barium hydroxide and aqueous iron chloride leads to barium chloride and iron hydroxide. This reaction is shown below:
- Ba(OH)2 + FeCl3 → BaCl2 + Fe(OH)3
Moreover, in these products, the iron hydroxide will form a solid substance that precipitates in the bottom of the container, while the barium chloride is more likely to maintain its liquid state.
According to this, the substance in the bottom is the iron hydroxide or Fe (OH)2, and in this, the yellow dots represent the Hydroxide or OH, while the blue dots are the Iron considering there in iron hydroxide there are two molecules of OH for each molecule of iron.
On the other hand, at the top, there is the barium chloride or BaCl2. This means the green dots are the Barium and the red ones are the Chlorine as there should be more Chlorine particles than Barium ones
Learn more in: brainly.com/question/19595631
Answer:
Twice as much.
Explanation:
That's because the freezing point depression depends on the total number of solute particles.
C₆H₁₂O₆(s) ⟶ C₆H₁₂O₆(aq)
0.01 mol of C₆H₁₂O₆ gives 0.01 mol of solute particles.
NaCl(s) ⟶ Na⁺(aq) + Cl⁻(aq)
1 mol of NaCl gives 0.01 mol of Na⁺(aq) and 0.01 mol of Cl⁻(aq).
That's 0.02 mol of particles, so the freezing point depression of 0.01 mol·L⁻¹ NaCl will be twice that of 0.01 mol·L⁻¹ C₆H₁₂O₆.
