Question

A package of aluminum foil contains 50. ft2 of foil, which weighs approximately 7.5 oz . Aluminum has a density of 2.70 g/cm3. What is the approximate thickness of the foil in millimeters?

Answer 1

Answer:

The thickness of the foil is 0.017 mm.

Explanation:

Given that,

Weight = 7.5 oz = 212.6175 gm

Density = 2.70 g/cm³

Area of aluminium = 50 ft² = 46451.52 cm²

We need to calculate the thickness of the foil

Using formula of density

$\rho=\dfrac{m}{V}$

$\rho=\dfrac{m}{A\times t}$

$t=\dfrac{m}{A\times \rho}$

Where, A = area

t = thickness

m = mass

Put the value into the formula

$t=\dfrac{212.6175}{46451.52\times2.70}$

$t=0.00170\ cm$

$t=0.017\ mm$

Hence, The thickness of the foil is 0.017 mm.