The correct answer is: [C]: "polar" .
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" Water " ; which is: " H₂O " ;
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is a:
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— polar; → {eliminate: "Choice [A]: "non-polar"} ;
→ {and consider: "Choice: [C]: "polar" } ;
— covalent; → {not "ionic"; eliminate: "Choice: [B]: "ionic"} ;
— uncharged; → {neutral compound; not "charged" —but "balanced"} ;
→ {Note: " H ⁺ , O ²⁻ ; → " H₂O " } ;
→ The "charges" balance/ cancel out.
→ {eliminate: "Choice: [D]: "charged" .}.
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— compound.
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The correct answer is: [C]: "polar" .
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Answer:
sample C have the highest density
Explanation:
Data Given:
mass of sample A = 224.96 g
Convert g to kg
1 g = 0.001 Kg
224.96 g = 224.96 x 0.001 = 0.225 kg
mass of sample B = 0.55632 Ibs
Convert lbs to kg
2.21 lb = 1 kg
0.55632 Ibs = 0.55632 / 2 = 0.278 kg
mass of sample C = 0.30648 kg
Solution:
To calculate density of every sample we have the following formula
d = m/v . . . . . . . . . . (1)
It is clear from the formula that density have direct relation with mass and inverse relation with volume, that is density increase with increasing in mass.
As we have same volume of wood sample, so suppose that each sample have volume of 2 cm³
So now we find density for each sample
As for sample A
- mass of sample A = 0.225 kg
Put values in formula 1
d = 0.225 kg / 2 cm³
d = 0.128 kg/cm³
As for sample B
- mass of sample A = 0.278 kg
Put values in formula 1
d = 0.278 kg / 2 cm³
d = 0.139 kg/cm³
As for sample C
- mass of sample C = 0.30648 kg
Put values in formula 1
d = 0.30648 kg / 2 cm³
d = 0.153 kg/cm³
So it shows that sample C have the highest density that is 0.153 kg/cm³ . As it have the highest mass too among all samples.
Cool dry air meeting warm Moist air
Answer:
An heater, Oven, sun, and fireplaces
Chose which ever you want
Mass of SiC = 2 g
<h3>Further explanation</h3>
Given
Reaction
SiO₂(s) + 3C(s) → SiC(s) + 2CO(g)
3.00 g of SiO₂
4.50 g of C
Required
mass of SiC
Solution
mol SiO₂ (MW=60,08 g/mol) :
= 3 g : 60.08 g/mol
= 0.0499
mol C(Ar = 12 g/mol) :
= 4.5 g : 12 g/mol
= 0.375
mol : coefficient of reactants =
SiO₂ : 0.0499/1 = 0.0499
C : 0.375/3 = 0.125
SiO₂ as a limiting reactant(smaller ratio)
Mol SiC based on mol SiO₂ = 0.0499
Mass SiC :
= mol x MW
= 0.0499 x 40,11 g/mol
= 2 g