17.40 sec is the time will take to smell second perfume after diffusion takes place
Acc. to Graham's law of Diffusion
Diffusion of Gas inversely proportional to square root of its Molecular mass.
<u>rb (Perfume B)</u>
ra(perfume A)
=
its equation (1)
Give molar mass of Perfume A = 275 g/mol
molar mass of Perfume B= 205g/mol putting value in (1)
» 
<em> its eq (2)</em>
» Perfume B will defuse 1:16 times faster than perfume A.
Hence, perfume B will be first smelled by Person.
Sf Equal volume V of two goes diffuse in t1 and t2 sec. respectively ton

Now,, from eq(2) toto
1/1:15 = 
ta
Given tb =the smell of Perfume B as it diffuse faster
ta= 1.15 x 15 see
=ta2=17.40 sec
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Answer:
There are 54.03 grams in 3 moles of H2O
There are 3.2 moles in 519.3 g FeCl3
There are 56.0 g in 2 moles of CO
Explanation:
H2O molar mass: 18.01 g/mol
to calculate the grams: 3 mol H2O * 18.01 g/mol
FeCl3 molar mass: 162.2 g/mol
to calculate moles: 519.3g FeCl3 / 162.2 g/mol
CO molar mass: 28.01 g/mol
to calculate grams: 28.01 g/mol CO * 2 mol CO
All alcohols are polar.
True