Question

A 7.00-mL portion of 8.00 M stock solution is to be diluted to 0.800 M. What will be the final volume after dilution? Enter your answer in scientific notation. Be sure to answer all parts. x 10 (select)L

Answer 1

Explanation:

The number of moles of solute present in liter of solution is defined as molarity.

Mathematically,         Molarity = $\frac{\text{no. of moles}}{\text{Volume in liter}}$

Also, when number of moles are equal in a solution then the formula will be as follows.

                     $M_{1} \times V_{1} = M_{2} \times V_{2}$

It is given that $M_{1}$ is 8.00 M, $V_{1}$ is 7.00 mL, and $M_{2}$ is 0.80 M.

Hence, calculate the value of $V_{2}$ using above formula as follows.

                    $M_{1} \times V_{1} = M_{2} \times V_{2}$

                 $8.00 M \times 7.00 mL = 0.80 M \times V_{2}$

                      $V_{2} = \frac{56 M. mL}{0.80 M}$

                                  = 70 ml

Thus, we can conclude that the volume after dilution is 70 ml.