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Yuri [45]
3 years ago
9

2.Look up Boyle’s law in a science textbook. How do the results of the experiment support or contradict Boyle’s law?

Chemistry
2 answers:
schepotkina [342]3 years ago
8 0
Boyle's law states that if temperature is held constant, pressure and volume are inversely proportional. An experiment may contradict this if volume and pressure are observed to be directly proportional.
MakcuM [25]3 years ago
3 0

<u>Answer;</u>

Based on the data the <u>pressure of the gas decreases while the volume increases</u>, according to the Boyle's Law.

The results of the experiment <u>support </u>Boyle's law because the two variables; <u>the volume and the pressure are inversely proportional</u>.

<h3><u>Explanation;</u></h3>
  • Boyle’s Law explains the relationship between the pressure and volume of an ideal gas when the temperature and amount of gas inside a container remain constant.
  • According to Boyle's Law as the volume of a gas increases, the pressure decreases, and as the volume of the gas decreases, the pressure of the gas  increases.
  • The evidence of an experiment would support the law if the the volume and the pressure of a gas are inversely proportional,
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The given sentence is part of a longer question.

I found this question with the same sentence. So, I will help you using this question:

For the reaction N2O4<span>(g) ⇄ 2NO</span>2(g), a reaction mixture at a certain temperature initially contains both N2O4 and NO2 in their standard states (meaning they are gases with a pressure of 1 atm<span>).  If </span>Kp = 0.15, which statement is true of the reaction mixture before any reaction occurs?


(a) Q = K<span>;   The reaction </span>is at equilibrium.
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Kp is the equilibrium constant in term of the partial pressures of the gases.

Q is the reaction quotient. It is a measure of the progress of a chemical reaction.

The reaction quotient has the same form of the equilibrium constant but using the concentrations or partial pressures at any moment.

At equilibrium both Kp and Q are equal. Q = Kp

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Here, the state is that both pressures are 1 atm, so Q = (1)^2 / 1 = 1.

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