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Semenov [28]
3 years ago
5

Calculate the mass of butane needed to produce 46.4 g of carbon dioxide

Chemistry
1 answer:
Alenkinab [10]3 years ago
8 0
Molar mass:

CH₄ = 12 + 1 x 4 = 16.0 g/mol

CO₂ = 12 + 16 x 2 = 44.0 g/mol

Balanced <span>equation :
</span>
<span>CH</span>₄<span> + 2 O</span>₂<span> = CO</span>₂<span> + 2 H</span>₂<span>O
</span>
16.0 g CH₄ --------------- 44.0 g CO₂
(mass of CH₄) ----------- 46.4 g CO₂

mass of CH₄ = 46.4 x 16.0 / 44.0

mass of CH₄ = 742.4 / 44.0

= 16.87 g CH₄

hope this helps!
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3 years ago
Calcular la presión final de un gas que inicialmente está a 21°C y 0,98 atm. Sabiendo que su temperatura aumenta a 37°C.
KatRina [158]

Answer:

1.03 atm

Explanation:

Primero <u>convertimos 21 °C y 37 °C a K</u>:

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  • 37 °C + 273.16 = 310.16 K

Una vez tenemos las temperaturas absolutas, podemos resolver este problema usando la<em> ley de Gay-Lussac</em>:

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En este caso:

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  • P₂ = ?
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7 0
3 years ago
Hydrogen sulfide decomposes according to the following reaction: 2H2S(g) ⇋ 2H2(g) + S2(g) Kc=9.30x10-8 at 700.°C.If 0.45 mol of
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Answer:

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We <u>put the data in the Kc expression and solve for x</u>:

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\frac{4x^3}{0.0225-4x^2}=9.30*10^{-8}

We make a simplification because x<<< 0.0225:

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