How many grams of sucrose would you add to water to make a total of 2.1 L of 9 % solution (mass per volume)? Make your answer's
1 answer:
Answer : The mass of sucrose added to water will be, 189.0 grams.
Explanation :
As we are given that 9 % solution (mass per volume) that means 9 grams of sucrose present in 100 mL volume of solution.
Total given volume of solution = 2.1 L = 2100 mL (1 L = 1000 mL)
Now we have to determine the mass of sucrose in solution.
As, 100 mL of solution contains 9 grams of sucrose
So, 2100 mL of solution contains grams of sucrose
Therefore, the mass of sucrose added to water will be, 189.0 grams.
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Answer : The volume of will be, 514.11 ml
Explanation :
The balanced chemical reaction will be,
First we have to calculate the mass of in tablet.
Now we have to calculate the moles of .
Molar mass of = 1 + 12 + 3(16) = 61 g/mole
Now we have to calculate the moles of .
From the balanced chemical reaction, we conclude that
As, 1 mole of react to give 1 mole of
So, 0.0202 mole of react to give 0.0202 mole of
The moles of = 0.0202 mole
Now we have to calculate the volume of by using ideal gas equation.
where,
P = pressure of gas = 1.00 atm
V = volume of gas = ?
T = temperature of gas =
n = number of moles of gas = 0.0202 mole
R = gas constant = 0.0821 L.atm/mole.K
Now put all the given values in the ideal gas equation, we get :
Therefore, the volume of will be, 514.11 ml