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atroni [7]
3 years ago
14

How many grams of sucrose would you add to water to make a total of 2.1 L of 9 % solution (mass per volume)? Make your answer's

precision to one decimal place.
Chemistry
1 answer:
s344n2d4d5 [400]3 years ago
8 0

Answer : The mass of sucrose added to water will be, 189.0 grams.

Explanation :

As we are given that 9 % solution (mass per volume) that means 9 grams of sucrose present in 100 mL volume of solution.

Total given volume of solution = 2.1 L = 2100 mL    (1 L = 1000 mL)

Now we have to determine the mass of sucrose in solution.

As, 100 mL of solution contains 9 grams of sucrose

So, 2100 mL of solution contains \frac{2100mL}{100mL}\times 9g=189.0 grams of sucrose

Therefore, the mass of sucrose added to water will be, 189.0 grams.

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Ivan

Answer:

56.28 g

Explanation:

First change the grams of oxygen to moles.

(50.00 g)/(32.00 g/mol) = 1.5625 mol O₂

You have to use stoichiometry for the next part.  Looking at the equation, you can see that for every 2 moles of H₂O, 1 mole of O₂ is produced.  Convert from moles of O₂ to moles of H₂O using this relation.

(1.5625 mol O₂) × (2 mol H₂O/1 mol O₂) = 3.125 mol H₂O

Now convert moles of H₂O to grams.

(3.125 mol) × (18.01 g/mol) = 56.28125 g

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