Answer:
<h2>12.5 N</h2>
Explanation:
The force acting on an object given it's mass and acceleration can be found by using the formula
force = mass × acceleration
From the question we have
force = 5 × 2.5
We have the final answer as
<h3>12.5 N</h3>
Hope this helps you
To minimize the material usage we have to have the volume requested with the minimum surface area.
The volume is:

And the surface is:

From the first equation we get:

I will use k instead of a number just for the conveince.
We plug this into the second equation and we get:

To find the minimum of this function we have to find the zeros of its first derivative.
Sx will denote the first derivative with respect to x and Sy will denote the first derivative with respect to Sy.

Now let both derivatives go to zero and solve the system (this will give us the so-called critical points).

Now we plug in the first equation into the other and we get:

Now we can calculate y:

And finaly we calculate z:

And finaly let's check our result:
1 horsepower is equivalent to 0.7457
Kilo Newton. I am hoping that this answer has satisfied your query and it will
be able to help you in your endeavor, and if you would like, feel free to ask
another question.
Answer:
10.21°C
Explanation:
From the question,we are given;
- Quantity of heat = 32,000 Joules
- Mass of water = 750 g
- Specific heat capacity of water = 4.18 J/g°C
We are required to calculate the change in temperature;
- We need to know that quantity of heat is calculated by multiplying mass by specific heat then by change in temperature.
- That is;
Q = m × c × ΔT
Rearranging the formula;
ΔT = (Q ÷ (m × c))
= 32,000 J ÷ (750× 4.18 J/g°C)
= 10.21°C
Therefore, the change in temperature is 10.21°C