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lisabon 2012 [21]
3 years ago
11

You drop a rock from rest from the top of a tall building.1)how far has the rock fallen in 2.60 s?

Physics
1 answer:
Bess [88]3 years ago
7 0
Answer:
distance = 33.124 meters

Explanation:
To solve this question, we will use one of the equations of motion which is:
s = ut + 0.5a * t^2
where:
s is the distance that we want to get
u is the initial velocity = 0
a is the acceleration due to gravity = 9.8 m/sec^2
t is the time = 2.6 sec

Substitute with the givens in the equation to get the distance as follows:
s = ut + 0.5a * t^2
s = (0)(2.6) + 0.5(9.8)(2.6)^2
s = 33.124 meters

Hope this helps :)
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Answer:

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Explanation:

From the question we are told that

     The length of the warbler is  L = 14cm = \frac{14}{100} = 0.14m

      The distance from the binoculars is    d = 18cm = \frac{18}{100} = 0.18m

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Without the 8 X binoculars the  angle made with the angular size of the object  is mathematically represented as

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Now magnification can be represented mathematically as

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Where \theta_z is the angle the image of the warbler subtend on your retina when the   binoculars i.e the  binoculars zoom.

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      \theta_z = M * \theta

=>    \theta_z =8 * 0.007778

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Generally the conversion to degrees can be mathematically evaluated as

             \theta_z = 0.062222224 * (\frac{360 }{2 \pi rad} )

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