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3 years ago

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The combustion of glucose, C6 H12 O6 (s), produces carbon dioxide, CO2 (g), and water, H2 O(g), according to the equation below.

The enthalpy of the reaction is –2,840 kJ. What is the heat of combustion, per mole, of glucose?

2 answers:

Serga [27]3 years ago

8 0

<span>I think that the answer is just -2,840 kJ/mol </span>

Andrei [34K]3 years ago

7 0

Answer:

A

Explanation:

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What element is NaCl?

ale4655 [162]

Sorry but NaCl is a ionic compound not an element though it's made up of two elements sodium and chlorine

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Calculate the molar mass of a 2.89 g gas at 346 ml, a temperature of 28.3 degrees Celsius, and a pressure of 760 mmHg.

malfutka [58]

The molar mass of gas = 206.36 g/mol

<h3>Further explanation</h3>

In general, the gas equation can be written

$\large{\boxed{\bold{PV=nRT}}}$

where

P = pressure, atm

V = volume, liter

n = number of moles

R = gas constant = 0.082 l.atm / mol K

T = temperature, Kelvin

mass (m)= 2.89 g

volume(V) = 346 ml = 0.346 L

T = 28.3 C + 273 = 301.3 K

P = 760 mmHg=1 atm

The molar mass (M) :

$\tt PV=\dfrac{m}{M}RT\\\\M=\dfrac{mRT}{PV}\\\\M=\dfrac{2.89\times 0.082\times 301.3}{1\times 0.346}\\\\M=206.36~g/mol$

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3 years ago

How many electrons are in the nucleus of an atom with 2 protons and 3 neutrons

strojnjashka [21]

Answer:

there'd be 2 electrons

Explanation:

number of electrons= number of protons

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3 years ago

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"Select True or False: The following data for the reaction: A(g) + 2B(s) === AB2(g) provides evidence that the reaction is exoth

galina1969 [7]

The reaction as shown is known to be an exothermic reaction.

<h2>Endothermic and exothermic reaction:</h2>

Depending on the temperature of the reaction vessel after reaction, the reaction could be classified as;

Endothermic
Exothermic

In an endothermic reaction, heat is absorbed and the rate of reaction increasing with increase in temperature while in an exothermic reaction, the rate of reaction decreases with increase in temperature.

Hence, the correct statements are;

The reaction is an exothermic reaction.
The value of K decreases as the value of T increases.

Learn more about exothermic reaction: brainly.com/question/14969584

7 0

3 years ago

Determine the empirical formula for compounds that have the following analyses: a. 66.0% barium and 34.0% chlorine b. 80.38% bis

almond37 [142]

Answer: a) $BaCl_2$

b) $BiO_3H_3$

Explanation:

If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

a) Mass of Ba= 66.06 g

Mass of Cl = 34.0 g

Step 1 : convert given masses into moles.

Moles of Ba = $\frac{\text{ given mass of ba}}{\text{ molar mass of Ba}}= \frac{66.06g}{137g/mole}=0.48moles$

Moles of Cl = \frac{\text{ given mass of Cl}}{\text{ molar mass of Cl}}= \frac{34g}{35.5g/mole}=0.96moles[/tex]

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For Ba = $\frac{0.48}{0.48}=1$

For O = $\frac{0.96}{0.48}=2$

The ratio of Ba: Cl= 1:2

Hence the empirical formula is $BaCl_2$

b) Mass of Bi= 80.38 g

Mass of O= 18.46 g

Mass of H = 1.16 g

Step 1 : convert given masses into moles.

Moles of Bi = $\frac{\text{ given mass of ba}}{\text{ molar mass of Ba}}= \frac{80.38g}{209g/mole}=0.38moles$

Moles of O= $\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{18.46g}{16g/mole}=1.15moles$

Moles of H= $\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{1.16g}{1g/mole}=1.16moles$

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For Bi= $\frac{0.38}{0.38}=1$

For O = $\frac{1.15}{0.38}=3$

For H= $\frac{1.16}{0.38}=3$

The ratio of Bi: O: H= 1:3: 3

Hence the empirical formula is $BiO_3H_3$

6 0

3 years ago