Question

Fluorine gas reacts with aqueous iron (II) iodide to produce aqueous iron (II) fluoride and iodine liquid. What is the balanced chemical equation for this reaction? Group of answer choices F+ Fe2 I → Fe2 F + FeI2 → FeF2 + I 2 F + FeI2 → FeF2 + 2 I F2 + 2 Fe2I → 2 Fe2 F + I2

Answer 1

Answer:

FeI₂(aq) + F₂(g) → I₂(l) + FeF₂(aq)

F + FeI2 → FeF2 + I 2

Explanation:

Fluorine gas reacts with aqueous iron (II) iodide to produce aqueous iron (II) fluoride and iodine liquid

Consider that the fluorine gas is a dyatomic molecule.

The other reactant is the FeI₂. As the iron acts with +2 in the oxidation state, we must have 2 atoms of iodide.

Therefore the products are: FeF₂ and I₂

It is a redox reaction where the iodide is oxidized to iodine and the fluorine is reduced to fluoride

2I⁻ → I₂ + 2e⁻   Half reaction oxidation

F₂  + 2e⁻ → 2F⁻  Half reaction reduction

We sum both: 2I⁻ + F₂  + 2e⁻ → I₂ + 2e⁻ + 2F⁻ and the electrons are removed.

2I⁻ + F₂  → I₂ + 2F⁻ so now, we add the iron, and the balanced reaction  is:

FeI₂ + F₂ → I₂ + FeF₂