An object with 10 protons 14 electrons and 5 neutrons would have what charge

When one person shouts at a football game, the sound intensity level at the center of the field is 58.4 dB. When all the people

Tanzania [10]

Answer:

The number of people at game are approximately 22909

Explanation:

Given data

When one person shout $\beta _{1}=58.4dB$

When n number of person shout together $\beta _{n}=102dB$

The sound intensity level during one person shout is given by:

$\beta _{1}=10log(\frac{I_{1}}{I_{o}} )\\58.4=10log(\frac{I_{1}}{I_{o}} )\\5.84=log(\frac{I_{1}}{I_{o}} )\\\frac{I_{1}}{I_{o}} =10^{5.84}\\I_{1}=10^{5.84}*I_{o}$

The sound intensity level during n number of person shout is given by:

$\beta _{n}=10log(\frac{I_{n}}{I_{o}} )\\102=10log(\frac{I_{n}}{I_{o}} )\\10.2=log(\frac{I_{n}}{I_{o}} )\\\frac{I_{n}}{I_{o}}=10^{10.2}\\I_{n}=10^{10.2}*I_{o}$

Since each person generates same sound intensity and hence total number of persons can be determined as

$=\frac{I_{n}}{I_{1}}\\ =\frac{10^{10.2}I_{o}}{10^{5.84}I_{o}} \\=22909$

Hence

The number of people at game are approximately 22909

3 0

3 years ago

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A machine exerts a 100 N force to the right over a 5.00 meter length in 4.00 seconds. Calculate the power output of this machine

bixtya [17]

125 W is the power output of this machine.

Answer:

Explanation:

Power is defined as the amount of work done on the system to move that system from its original state within the given time interval. So it can be determined by the ratio of work done with time interval. As work done is the measure of force required to move a system to a certain distance. Work done is calculated as product of force with displacement.

So in the present case, the force is given as 100 N, the displacement is given as 5 m and the time is given as 4 s, then power is

$Power = \frac{Work done}{Time}$

As Work done = Force acting on the machine × Displacement

So $Power = \frac{(Force * Displacement)}{Time}$

Power = $\frac{(100*5)}{4}$ =125 W

So, 125 W is the power output of this machine.

6 0

3 years ago

A mass weighing 4 pounds is attached to a spring whose constant is 2 lb/ft. The medium offers a damping force that is numericall

Ad libitum [116K]

Answer:

t = 025 s

Explanation:

We know

weight, W = 4 pounds

spring constant, k = 2 lb/ft

Positive damping, β = 1

Therefore mass, m = W / g

m = 4 / 32

= 1 / 8 slug

From Newtons 2nd law

$\frac{d^{2}x}{dt^{2}}=-kx-\beta .\frac{dx}{dt}$

where x(t) is the displacement from the mean or equilibrium position. The equation can be written as

$\frac{d^{2}x}{dt^{2}}+\frac{\beta }{m}.\frac{dx}{dt}+\frac{k}{m}x=0$

Substituting the values, the DE becomes

$\frac{d^{2}x}{dt^{2}}+8\frac{dx}{dt}+16x=0$

Now the equation is

$m^{2}+8m+16=0$

and on solving the roots are

$m_{1}$ = $m_{2}$ = -4

Therefore the general solution is $x(t)=e^{-4t}\left ( c_{1}+c_{2}t \right )$

Now for initial condition x(0) = -1 ft

x'(0)= 8 ft/s

Now we can find the equation of motion becomes,

$x(t)=e^{-4t}\left ( -1+4t \right )$

Therefore, the mass passes through the equilibrium when

x(t) = 0

$e^{-4t}\left ( -1+4t \right )$ = 0

-1+4t = 0

t = $\frac{1}{4}$

= 0.25 s

8 0

3 years ago

What is Hubbles Law?

Whitepunk [10]

Answer:

Explanation:

Hubble's law is considered the first observational basis for the expansion of the universe and today serves as one of the pieces of evidence most often cited in support of the Big Bang model.The motion of astronomical objects due solely to this expansion is known as the Hubble flow.

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3 years ago

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A 4kg block slides freely across a rough surface such that the block slows down with an acceleration of −1.25 m/s2 . What is the

Sophie [7]

Answer:

The coefficient of kinetic friction between the block and the surface is 0.127.

Explanation:

Given that,

The mass of a block, m = 4 kg

The acceleration of the block, a = -1.25 m/s²

We need to find the coefficient of kinetic friction between the block and the surface. The force of friction is given by :

$F=\mu mg\\\\ma=\mu mg\\\\\mu=\dfrac{a}{g}\\\\\mu=\dfrac{1.25}{9.8}\\\\\mu=0.127$

So, the coefficient of kinetic friction between the block and the surface is 0.127.

6 0

3 years ago