Answer:
Explanation:
Firstly, when you measure the voltage across the battery, you get the emf,
E = 13.0 V
In order to proceed we have to assume that the voltmeter offers no loading effect, which is a valid assumption since it has a very high resistance.
Secondly, the wires must be uniform. So the resistance per unit length is constant (say z). Now, even though the ammeter has very little resistance it cannot be ignored as it must be of comparable value/magnitude when compared to the wires. This is can seen in the two cases when currents were measured. Following Ohm's law and the resistance of a length of wire being proportional to it's length, we should have gotten half the current when measuring with the 40 m wire with respect to the 20 m wire (
). But this is not the case.
Let the resistance of the ammeter be r
Hence, using Ohm's law we get the following 2 equations:
.......(1)
......(2)
Substituting the value of r from (2) in (1), we have,
which simplifying gives us, 
(which is our required solution)
putting the value of z in either (1) or (2) gives us, r = 0.5325 
Hello,
Here is your answer:
The proper answer for this question is option B "When released,a book falls to the ground". That's because of gravity the book will hit the ground!
Your answer is B.
If you need anymore help feel free to ask me!
Hope this helps.
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Correct me if I’m wrong, but I believe it’s A and D, though I’m not fully sure.
Answer:
It will double.
Explanation:
Newton's Law of Gravity states that 
, where G is the gravitational constant, <em>r</em> is the distance between the objects' centers, and 
and 
are the objects' masses. We just have simple math here: by doubling , we double the entire fraction. By doubling the entire fraction, we double the gravitational pull. Therefore, <em>Newton's Law of Gravity states that if the mass of one object doubles, the gravitational pull on a second object will </em><em>double</em><em>.</em>
I hope this helps you understand it! Have a great day, 'kay?
