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Wittaler [7]
3 years ago
7

How can iodine ( Z = 53) have a higher atomic number yet a lower atomic mass than telluriurn ( Z = 52)?

Chemistry
1 answer:
Leokris [45]3 years ago
7 0

Answer:

Iodine have higher atomic size than tellurium because of the presence of more number of protons and lower atomic mass than tellurium because of the presence of lower number of neutrons.

Explanation:

Atomic number of an element is the number of the protons present in the element.

Atomic mass is the sum of a protons and the neutrons which are present in the nucleus of the atom.

Iodine has higher atomic number than tellurium because it has more number of protons than the tellurium.

On the other hand, iodine has lower atomic mass than tellurium because it has less number of neutrons in its core.

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Suppose these substance were placed in a freezer set to -50 grades celsius. Which substance would become a liquid. Clorine, Merc
Vadim26 [7]
Chlorine would become a liquid. Its boiling point is around -34 Celsius so at any temperature below that it would be liquid.
5 0
3 years ago
Iodine, I2, is a solid at room temperature but sublimes (converts from a solid into a gas) when warmed. What is the temperature
Stels [109]
<h3>Answer:</h3>

382.63 K

<h3>Explanation:</h3>

We are given;

  • Volume of Iodine as 71.4 mL
  • Mass of Iodine as 0.276 g
  • Pressure of Iodine as 0.478 atm

We are required to calculate the temperature of Iodine

  • We are going to use the ideal gas equation;
  • According to the ideal gas equation; PV = nRT, where R is the ideal gas constant, 0.082057 L.atm/mol.K.
  • Rearranging the formula;

T = PV ÷ nR

But, n, the number of moles = Mass ÷ Molar mass

Molar mass of iodine = 253.8089 g/mol

Thus, n = 0.276 g ÷ 253.8089 g/mol

           = 0.001087 moles

Therefore;

T = (0.478 atm × 0.0714 L) ÷ (0.001087 moles × 0.082057)

  = 382.63 K

Thus, the temperature of Iodine in Kelvin is 382.63 K

3 0
3 years ago
How much nano3 is needed to prepare 225 ml of a 1.55 m solution of nano3?
andrezito [222]

Answer:

= 29.64 g  NaNO3

Explanation:

Molarity is given by the formula;

Molarity = Moles/Volume in liters

Therefore;

Number of moles = Molarity × Volume in liters

                             = 1.55 M × 0.225 L

                             = 0.34875 moles NaNO3

Thus; 0.34875 moles of NaNO3 is needed equivalent to;

   = 0.34875 moles × 84.99 g/mol

   = 29.64 g

5 0
3 years ago
A 1.5 M solution of NaOH was made in a laboratory. If the solution made had a volume of 4.5 L, how many grams of NaOH were added
Crank

Answer:

270g

Explanation:

Given parameters:

Concentration of NaOH  = 1.5M

Volume  = 4.5L

Unknown

Mass of NaOH added  = ?

Solution:

To solve the problem, we need to find the number of moles of the NaOH first;

 Number of moles  = concentration x volume

 Number of moles  = 1.5 x 4.5  = 6.75mol  

Now;

  Mass  = Number of moles x molar mass

 Molar mass of NaOH  = 23 + 16 + 1  = 40g/mol

  Mass  = 6.75 x 40  = 270g

6 0
3 years ago
Is oxygen an element?
laiz [17]
Yes oxygen is an element it is
the 8th element 
the second period
16th group
noble gas configuration [He]2s^22p^4
7 0
3 years ago
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