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3 years ago

How can iodine ( Z = 53) have a higher atomic number yet a lower atomic mass than telluriurn ( Z = 52)?

Chemistry

1 answer:

Leokris [45]3 years ago

7 0

Answer:

Iodine have higher atomic size than tellurium because of the presence of more number of protons and lower atomic mass than tellurium because of the presence of lower number of neutrons.

Explanation:

Atomic number of an element is the number of the protons present in the element.

Atomic mass is the sum of a protons and the neutrons which are present in the nucleus of the atom.

Iodine has higher atomic number than tellurium because it has more number of protons than the tellurium.

On the other hand, iodine has lower atomic mass than tellurium because it has less number of neutrons in its core.

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Odor extensive or intensive

slava [35]

Answer:

Odour is intensive

Explanation:

intensive properties are Independent of the amount of matter

6 0

3 years ago

Why do crisp packets become inflated at high altitudes? Again, explain in as great a detail as possible, using ideas about parti

Andrei [34K]

As you get higher the atmospheric pressure lowers. The pressure in the packet of crisps has the pressure at which it has been closed (pressure at the surface of the earth). This means that the air molecules in the packet press harder outside than the air molecules in the atmosphere press on the packet.

3 0

3 years ago

What is the ratio between the mass of nitrogen and oxygen in N2O3?

Ket [755]

Answer:

12:7

Explanation:

To Determine: To calculate the formula of the unknown binary compound of oxygen and nitrogen and to ratio in the next compound of the series using given data.Answer:The formula of the unknown compound .The ratio for atoms of oxygen to nitrogen inis .The mass ratio of oxygen to nitrogen in next member of the series of compounds is .Explanation:The mass ratio of toinis .The mass ratio of toin theunknown compound is .The atomic mass of the oxygen is .The atomic mass of the nitrogen is .The mass ratio of to in a molecule can be represented as: …… (1)Here,is the number of atoms of the oxygen in the molecule.is the mass of an atom of oxygen.is the number of atoms of the nitrogen in the molecule.is the mass of an atom of nitrogen.For unknown compound, substitutefor , for and for mass ratio in equation (1).The ratio of atoms of oxygen to nitrogen is , therefore, the expected formulas of the unknown compound is and . If the unknown compound is in a series with then the formula of the unknown compound and the formula for the next member of the series is .The ratio for atoms of oxygen to nitrogen inis .For , substitute 5 for , for , 2 for and for in equation (1).The mass ratio of oxygen to nitrogen in next member of the series of the compounds is .

6 0

3 years ago

Question 4 point

Ronch [10]

Answer:

$5393.4gH_2O$

Explanation:

Hello there!

In this case, for the described chemical reaction, we can write:

$CH_4+2O_2\rightarrow CO_2+2H_2O$

Thus, by considering the 1:2 mole ratio of methane to water, and the molar mass of the latter (18.02 g/mol), the following is useful to calculate the mass of water that is produced:

$149.65molCH_4*\frac{2molH_2O}{1molCH_4} *\frac{18.02gH_2O}{1molH_2O}$

Which is equal to:

$5393.4gH_2O$

Which is not among the choices.

Regards!

5 0

3 years ago

PLS ANSWER ASAP, WILL GIVE BRAINLIEST ANSWER

Stolb23 [73]

Answer:

.14L or 140mL

Explanation:

This is a classic plug-n-chug problem. Your textbook probably goes over this formula as $M_{1}V_{1} = M_{2}V_{2}$ . M stands for molarity of the given substance, and V stands for the volume that the substance occupies.

Simply plug in the values that you're given, like so:

$M_{1} = 1.5M\\V_{1} = ???\\M_2 = 7M\\V_2 = .03L$

$1.5M * x = 7M * .03L$

After completing the algebra portion and solving for the unknown, you will be left with x = .14L, which is the volume required to neutralize 30mL of 7M NaOH.

6 0

3 years ago