Chlorine would become a liquid. Its boiling point is around -34 Celsius so at any temperature below that it would be liquid.
<h3>
Answer:</h3>
382.63 K
<h3>
Explanation:</h3>
We are given;
- Volume of Iodine as 71.4 mL
- Mass of Iodine as 0.276 g
- Pressure of Iodine as 0.478 atm
We are required to calculate the temperature of Iodine
- We are going to use the ideal gas equation;
- According to the ideal gas equation; PV = nRT, where R is the ideal gas constant, 0.082057 L.atm/mol.K.
T = PV ÷ nR
But, n, the number of moles = Mass ÷ Molar mass
Molar mass of iodine = 253.8089 g/mol
Thus, n = 0.276 g ÷ 253.8089 g/mol
= 0.001087 moles
Therefore;
T = (0.478 atm × 0.0714 L) ÷ (0.001087 moles × 0.082057)
= 382.63 K
Thus, the temperature of Iodine in Kelvin is 382.63 K
Answer:
= 29.64 g NaNO3
Explanation:
Molarity is given by the formula;
Molarity = Moles/Volume in liters
Therefore;
Number of moles = Molarity × Volume in liters
= 1.55 M × 0.225 L
= 0.34875 moles NaNO3
Thus; 0.34875 moles of NaNO3 is needed equivalent to;
= 0.34875 moles × 84.99 g/mol
= 29.64 g
Answer:
270g
Explanation:
Given parameters:
Concentration of NaOH = 1.5M
Volume = 4.5L
Unknown
Mass of NaOH added = ?
Solution:
To solve the problem, we need to find the number of moles of the NaOH first;
Number of moles = concentration x volume
Number of moles = 1.5 x 4.5 = 6.75mol
Now;
Mass = Number of moles x molar mass
Molar mass of NaOH = 23 + 16 + 1 = 40g/mol
Mass = 6.75 x 40 = 270g
Yes oxygen is an element it is
the 8th element
the second period
16th group
noble gas configuration [He]2s^22p^4