24 gFeF3 x (1 mol FeF3/grams FeF3)
x (6.02x10^23 molecules FeF3/ 1 mol FeF3)
Just Calculate Molar Mass of FeF3 and plug into equation
Answer:
Sedimentary rocks are the product of 1) weathering of preexisting rocks, 2) transport of the weathering products, 3) deposition of the material, followed by 4) compaction, and 5) cementation of the sediment to form a rock. The latter two steps are called lithification.
Answer:
0.00011 JK.
The process does NOT violate the second law of thermodynamics
Explanation:
The following parameters are given which are going to help in solving for the change in entropy of the system. The term "entropy'' simply means the degree of disorderliness of a system.
=> The temperature of container A = 305 K, the temperature of container B = 295 K and the amount of heat generated when the containers are placed in contact with each other = 1. 1 J.
The change in entropy of the hot container = -(1/305) = - 0.00328 J/K.
The change in entropy of the cold container = 1/295 = 0.00339 J/K.
Therefore, the change in the entropy of the system = - 0.00328 J/K + 0.00339 J/K = 0.00011 JK.
Note that the change in entropy of the system gives a positive value. Hence, this process does not violate the second law of thermodynamics.
The process does NOT violate the second law of thermodynamics.
Answer:
I'm not sure if this right because i've only taken one year of Chemistry but the answer I got was
A. 24 g
