Answer:

Explanation:
The first step in this reaction is the<u> converstion from Kg</u> of
<u>to</u> <u>grams</u> of
.


Then we can calculate the <u>percentage</u> of
in the sample:


D have the same opinion on the contain resisting
Answer:
1.09 L
Explanation:
There is some info missing. I think this is the original question.
<em>Calculate the volume in liters of a 0.360 mol/L barium acetate solution that contains 100 g of barium acetate. Be sure your answer has the correct number of significant digits.</em>
<em />
The molar mass of barium acetate is 255.43 g/mol. The moles corresponding to 100 grams are:
100 g × (1 mol/255.43 g) = 0.391 mol
0.391 moles of barium acetate are contained in an unknown volume of a 0.360 mol/L barium acetate solution. The volume is:
0.391 mol × (1 L/0.360 mol) = 1.09 L
Answer:
7
8
9
10.
better check book pages for this kinda answer.