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3 years ago

LLLLLLLLLLLLLLLLLLLL

Chemistry

1 answer:

Karo-lina-s [1.5K]3 years ago

5 0

Answer: I dont take L´s. Only W´s so ha!!!

Explanation: Lol just messin with ya. I actually dont know what your question is but have a good one, and stay safe!! :))

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The emission of NO₂ by fossil fuel combustion can be prevented by injecting gaseous urea into the combustion mixture. The urea r

liq [111]

Answer:

There is 709.1 grams of urea needed.

Explanation:

Step 1: The balanced equation:

2CO(NH2)2(g)+4NO(g)+O2(g)→4N2(g)+2CO2(g)+4H2O(g)

Step 2: Data given

The exhaust stream of an automobile has a flow rate of 2.37 L/s

This happens at a temperature of 657 Kelvin

The partial pressure of NO is 14.0 torr

Step 3: Calculating the volume during 8.1 hours

V = 2.37L/s ∙ 8.1hr ∙3600s/hr = 69109.2L = 69.1092m³

Step 4: Calculate the partial pressure of nitric oxide:

p = 14 torr ∙ 101325Pa/760torr = 1866.5Pa

Step 5: Calculating number of moles of NO

⇒ We use the ideal gas law P*V=n*R*T

n(NO) = P*V/R*T

with P= The partial pressure of NO = 1866.5 Pa

with V =the volume of NO = 69.1092m³

with R = the gas constant = 8.314472 Pa*m³/mol*K

with T = 657 Kelvin

n(NO) = 1866.5Pa ∙ 69.1092m³ / (8.314472Pa*m³/mol*K ∙ 657K)

= 23.61 mol es

Step 6: Calculate moles of urea

Since there is consumed 2 moles of urea per 4 moles of nitric oxide.

This means for 24.432 moles of NO, there is consumed 23.61 /2 = 11.806 moles of urea.

Step 7: Calculate mass of urea

m(CO(NH₂)₂) = 11.806 moles ∙ 60.06g/moles = 709.07g

There is 709.1 grams of urea needed.

4 0

3 years ago

At a certain temperature, the vapor pressure of pure benzene ‍ is atm. A solution was prepared by dissolving g of a nondissociat

erastova [34]

Answer:

Molar mass of solute: 300g/mol

Explanation:

Vapor pressure of pure benzene: 0.930 atm

Assuming you dissolve 10.0 g of the non-volatile solute in 78.11g of benzene and vapour pressure of solution was found to be 0.900atm

It is possible to answer this question based on Raoult's law that states vapor pressure of an ideal solution is equal to mole fraction of the solvent multiplied to pressure of pure solvent:

$P_{sln} = X_{solvent}P_{solvent}^0$

Moles in 78.11g of benzene are:

78.11g benzene × (1mol / 78.11g) = 1 mol benzene

Now, mole fraction replacing in Raoult's law is:

0.900atm / 0.930atm = 0.9677 = moles solvent / total moles.

As mole of solvent is 1:

0.9677× total moles = 1 mole benzene.

Total moles:

1.033 total moles. Moles of solute are:

1.033 moles - 1.000 moles = 0.0333 moles.

As molar mass is the mass of a substance in 1 mole. Molar mass of the solute is:

10.0g / 0.033moles = 300g/mol

8 0

3 years ago

What is the ph of 0.1 m naoh solution??

Rudik [331]

NaOH is a strong base so pH will be around 13 to 12. Whatever number of moles of NaOH you have approximately the pH of NaOH will be around 14 13 or 12

7 0

4 years ago

1. Anthony walks to the pizza place for lunch. He walks 1km east then 1km south east again.

TiliK225 [7]

The answer is: distance is 3 km, displacement is 2.24 km.

Distance is total length: 1 km east + 1 km south + 1 km east again = 3 km
Displacement is the hypotenuse of the right triangles which sides are 1 km east and 2 km south. According to the Pythagorean theorem:
a² + b² = c²
1² + 2² = c²
1 + 4 = c²
5 = c²
c = √5
c = 2.24 km

8 0

4 years ago

Read 2 more answers

How many moles are in 24.3g of iron (II) oxide?

wlad13 [49]

Mark me Brainliest..... ......

6 0

3 years ago