Anyone know the answer to this ??

Mathematics

1 answer:

Hatshy [7]3 years ago

7 0

The first one : -6
the second : -14

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Find the arc length of the semicircle. Either enter an exact answer in terms of π or use 3.14 for π and enter your answer as a d

PSYCHO15rus [73]

Answer:

Step-by-step explanation:

The formula for the length of an arc is s = rФ.

Thus, the arc length of a semicircle is S = rФ/2.

Here the radius is 5 (half the diameter), and so in this case the arc length is

S = (5 units)π/2, or S = (5/2)(3.14) units, or approximately S = 7.85 units

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3 years ago

Help please! I need the area of this given figure. The formula is A=1/2(b1+b2)h

Pie

Answer:

108 ft

Correct me, if I am wrong :)

have a great day!

Thanks!

8 0

2 years ago

Read 2 more answers

A bag contains different colored candies. There are 50 candies in the bag, 28 are red, 10 are blue, 8 are green and 4 are yellow

Mrrafil [7]

Answer:

$\displaystyle \frac{54}{5405}$ .

Step-by-step explanation:

How many unique combinations are possible in total?

This question takes 5 objects randomly out of a bag of 50 objects. The order in which these objects come out doesn't matter. Therefore, the number of unique choices possible will the sames as the combination

$\displaystyle \left(50\atop 5\right) = 2,118,760$ .

How many out of that 2,118,760 combinations will satisfy the request?

Number of ways to choose 2 red candies out a batch of 28:

$\displaystyle \left( 28\atop 2\right) = 378$ .

Number of ways to choose 3 green candies out of a batch of 8:

$\displaystyle \left(8\atop 3\right)=56$ .

However, choosing two red candies out of a batch of 28 red candies does not influence the number of ways of choosing three green candies out of a batch of 8 green candies. The number of ways of choosing 2 red candies and 3 green candies will be the product of the two numbers of ways of choosing

$\displaystyle \left( 28\atop 2\right) \cdot \left(8\atop 3\right) = 378\times 56 = 21,168$ .