Answer:
A) E° = 4.40 V
B) ΔG° = -8.49 × 10⁵ J
Explanation:
Let's consider the following redox reaction.
2 Li(s) +Cl₂(g) → 2 Li⁺(aq) + 2 Cl⁻(aq)
We can write the corresponding half-reactions.
Cathode (reduction): Cl₂(g) + 2 e⁻ → 2 Cl⁻(aq) E°red = 1.36 V
Anode (oxidation): 2 Li(s) → 2 Li⁺(aq) + 2 e⁻ E°red = -3.04
<em>A) Calculate the cell potential of this reaction under standard reaction conditions.</em>
The standard cell potential (E°) is the difference between the reduction potential of the cathode and the reduction potential of the anode.
E° = E°red, cat - E°red, an = 1.36 V - (-3.04 V) 4.40 V
<em>B) Calculate the free energy ΔG° of the reaction.</em>
We can calculate Gibbs free energy (ΔG°) using the following expression.
ΔG° = -n.F.E°
where,
n are the moles of electrons transferred
F is Faraday's constant
ΔG° = - 2 mol × (96468 J/V.mol) × 4.40 V = -8.49 × 10⁵ J
Answer:
146
Explanation:
uranium is 92 and the mass number of the isotope is given as a 238 therefore it is not the two protons 92 electrons and
real explanation Google it
Answer:
2AL(ClO3)3 → 2ALCl3 + 9O2
Explanation:
Answer:
![CH_3 CH_2 CH_2 CH_2 CH_2 CH_2 CHO + 2[Ag(NH_3)_2]+ 3 H_2 O](https://tex.z-dn.net/?f=CH_3%20CH_2%20CH_2%20CH_2%20CH_2%20CH_2%20CHO%20%2B%202%5BAg%28NH_3%29_2%5D%2B%20%203%20H_2%20O)
= 
Explanation:
Tollens test is carried out to perceive difference between aldehydes and ketones on the basis of their capability to oxidized easily.
when Tollens react with aldehyde (heptanal) , a silver mirror is form on inner side of container.
The reaction between tollens and heptanal is given as
![CH_3 CH_2 CH_2 CH_2 CH_2 CH_2 CHO + 2[Ag(NH_3)_2]+ 3 H_2 O](https://tex.z-dn.net/?f=CH_3%20CH_2%20CH_2%20CH_2%20CH_2%20CH_2%20CHO%20%2B%202%5BAg%28NH_3%29_2%5D%2B%203%20H_2%20O)
= 
Answer:
True
Explanation:
Permanent artificial, temporary artificial and natural. They are classified by the way in which they have achieved magnetism and by how long they remain magnetic.
