1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Eva8 [605]
3 years ago
11

What type of reaction does each of the following equations represent?

Chemistry
1 answer:
vekshin13 years ago
3 0

Answer:

Option C. Decomposition

Explanation:

To know which option is correct, it is important we know what is a single displacement reaction, double displacement reaction and decomposition reaction.

A Single displacement reaction can be defined as a reaction in which a single element is replaced by another element in a compound.

A double displacement reaction is a reaction involving the exchange of ions of two parts of ionic compounds to form two different compounds.

A decomposition reaction is a reaction in which a compound splits into two or more simpler compound or element.

Bearing the above definitions in mind and considering the question given above, we can conclude that the reaction given in the question above is a decomposition reaction since the compound (NH₄OH) splits into two different compound (NH₃ and H₂O)

You might be interested in
Which of these is caused by a chemical change?
IRISSAK [1]
I think that is A is the answer.
8 0
3 years ago
What is the mass in milligrams of 4.30 moles of sodium?use âeâ for âÃ10" and use significant figures?
Elis [28]

First, calculate the mass of sodium in g with the help of molar mass and number of moles.

Number of moles = \frac{given mass in g}{molar mass}   (1)

Molar mass of sodium =23 .0 g/mol

Substitute the given value of number of moles and molar mass of sodium in formula (1)

4.30 moles = \frac{given mass in g}{23.0 g/mol}   (1)

4.30 moles\times 23.0 g/mol = mass in g   (1)

mass of sodium in g = 98.9 g

Now, according to conversion factor, 1 g = 1000 mg

So, 98.9 g of sodium = 98.9 \times 1000  mg

= 98900 mg of sodium

Thus, mass of sodium in mg  =9.89 \times 10^{4} mg






8 0
3 years ago
2. List and elaborate on at least two limitations of the 24-hour recall as a
Pavlova-9 [17]

Answer:

The correct answer is - may not be typical, and participant burden.

Explanation:

The 24-hour recall is nothing but a retrospective method of diet assessment. In this method, an individual is interviewed about his or her diet consumption during the last 24 hours.

The disadvantages or limitations of this method include the inability of a single day's intake to describe the typical diet, multiple recalls to intake, cost and administration time; participant burden, have to recall to reliably estimate usual intake.

5 0
3 years ago
In ____________ reactions, certain molecules are broken down; in the process they release energy which is captured when high-ene
Rudik [331]

Answer:

Exergonic ,Endergonic,low concentration area,high

Explanation:

In exergonic reaction,certain molecules are broken down;in the process they release energy which is captured when high energy molecules(such as ATP and NADH) are formed.

                          The breakdown of these molecules can be coupled to thermodynamically unfavorable processes such as Endergonic reactions or pumping og hydrogen ion from low concentration areas to high concentration areas.

3 0
3 years ago
The reaction C4H8(g)⟶2C2H4(g) C4H8(g)⟶2C2H4(g) has an activation energy of 262 kJ/mol.262 kJ/mol. At 600.0 K,600.0 K, the rate c
crimeas [40]

Answer : The rate constant at 785.0 K is, 1.45\times 10^{-2}s^{-1}

Explanation :

According to the Arrhenius equation,

K=A\times e^{\frac{-Ea}{RT}}

or,

\log (\frac{K_2}{K_1})=\frac{Ea}{2.303\times R}[\frac{1}{T_1}-\frac{1}{T_2}]

where,

K_1 = rate constant at 600.0K = 6.1\times 10^{-8}s^{-1}

K_2 = rate constant at 785.0K = ?

Ea = activation energy for the reaction = 262 kJ/mole = 262000 J/mole

R = gas constant = 8.314 J/mole.K

T_1 = initial temperature = 600.0K

T_2 = final temperature = 785.0K

Now put all the given values in this formula, we get:

\log (\frac{K_2}{6.1\times 10^{-8}s^{-1}})=\frac{262000J/mole}{2.303\times 8.314J/mole.K}[\frac{1}{600.0K}-\frac{1}{785.0K}]

K_2=1.45\times 10^{-2}s^{-1}

Therefore, the rate constant at 785.0 K is, 1.45\times 10^{-2}s^{-1}

7 0
3 years ago
Other questions:
  • Are spider multicellular
    6·1 answer
  • What is the density of sand if the volume is 40.0 ml and the mass is 62.3 g?
    14·2 answers
  • What particles do during phase changes
    10·1 answer
  • The densities of several gases at the same temperature are listed below. Considering only density, waves should travel fastest i
    5·2 answers
  • when a piece of potassium metal is placed in water a violent reaction occurs. when copper metal is placed in water nothing happe
    8·1 answer
  • Organs _____.
    12·1 answer
  • Compare the way that frogs breathe when they are tadpoles with the way frogs breathe when they are adults.
    7·2 answers
  • In order to heat a round bottom flask in a heating mantle, plug the heating mantle into _______.Turn the heat up _________, and
    7·1 answer
  • How can wind be used as a source of power?
    12·2 answers
  • Is hydrogen the only non-metal positive ion?
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!