can you please help me out with these questions! PLEASE DONT COMMENT ANYTHING IF U DONT HAVE THE ANSWERS!!!

What is the basic of Architecture?

kobusy [5.1K]

I believe your question is "What are the basics of Architecture?"

Answer:

Architecture is all about people, places and things.

Explanation:

In order to learn about the answer, let's tackle them one-by-one.

First, architecture is the art or practice of designing or constructing building. The basics are pretty simple.

1. People- this refers to the designers, builders and users. This means architecture is all about those who make architecture and those who use it in order to make conscious decisions. It is all about building an environment for people, thus it focuses too on builders. These environments are catered to users. For example, designing a safe place for disabled people.

2. Places- Traveling is very important in order for you to learn the different kinds of architectures in every country. It is, thus, very significant to know where one will build his plan. It is said that "the power of place" can be everlasting.

3. Things- this refers to the built environment. An example of these are the skyscrapers. These are considered to be the "things" that architects design in order to truly scrape the sky. In architecture, one needs to learn what structures and style he wants for his house, church, school, building and the like.

7 0

4 years ago

Harmony in music is characterized by _____.

stira [4]

Answer:

the vertical relationship of pitches.

Explanation:

Harmony can be defined as the use of simultaneous pitches ( two or more tones and notes) or chords played at the same time together.

Harmony in music is characterized by the vertical relationship of pitches. The three most popular and essential forms of harmony are;

1. Diatonic harmony.

2. Non-diatonic harmony.

3. Atonal harmony.

6 0

3 years ago

Read 2 more answers

Relation between Poisson's ration, young's modulus, shear modulus for an isotropic material

poizon [28]

Answer:

E=2 G(1+2μ)

Explanation:

Isotropic material :

Those material have same property in all direction is known as isotropic material.

Homogeneous material :

Those material have same property through out the volume is known as homogeneous material.

Relationship between Poisson ratio ,young modulus and shear modulus:

E=2 G(1+2μ)

Relationship between Poisson ratio ,bulk modulus and shear modulus:

E=2 K(1-μ)

Where

E is young modulus.

G is shear modulus.

μ is Poisson ratio.

8 0

3 years ago

A single crystal of a metal that has the BCC crystal structure is oriented such that a tensile stress is applied in the [100] di

VARVARA [1.3K]

Answer:

For [1 1 0] and [1 0 1] plane, σₓ = 6.05 MPa

For [0 1 1] plane, σ = 0; slip will not occur

Explanation:

compute the resolved shear stress in [111] direction on each of the [110], [011] and on the [101] plane.

Given;

Stress direction: [1 0 0] ⇒ A

Slip direction: [1 1 1]

Normal to slip direction: [1 1 1] ⇒ B

∅ is the angle between A & B

Step 1: cos∅ = A·B/|A| |B| = $\frac{[100][111]}{\sqrt{1}.\sqrt{3} }$ ⇒ cos∅ = 1/ $\sqrt{3}$

σₓ = τ/cos ∅·cosλ

where τ is the critical resolved shear stress given as 2.47MPa

Step 2: Solve for the slip along each plane

(a) [1 1 0]

cosλ = [1 1 0]·[1 0 0]/( $\sqrt{2}$ · $\sqrt{1}$ )

note: cosλ = slip D·stress D/|slip D||stress D|

cosλ = 1/ $\sqrt{2}$

∵ σₓ = τ/ $\frac{1}{\sqrt{2} }$ · $\frac{1}{\sqrt{3} }$ = $\sqrt{6}$ * 2.47MPa = 6.05MPa

Hence, stress necessary to cause slip on [1 1 0] is 6.05MPa

(b) [0 1 1]

cosλ = [0 1 1]·[1 0 0]/( $\sqrt{2}$ · $\sqrt{1}$ ) = 0

∵ σₓ = 2.47MPa/0, which is not defined

Hence, for stress along [1 0 0], slip will not occur along [0 1 1]

(c) [1 0 1]

cosλ = [0 1 1]·[1 0 0]/( $\sqrt{2}$ · $\sqrt{1}$ )

cosλ = 1/ $\sqrt{2}$

∵ σₓ = τ/ $\frac{1}{\sqrt{2} }$ · $\frac{1}{\sqrt{3} }$ = $\sqrt{6}$ * 2.47MPa = 6.05MPa

See attachment for the space diagram

3 0

3 years ago

Find the resultant of two forces 130 N and 110 N respectively, acting at an angle whose tangent

monitta

Answer:

$F_r = 200N$

Explanation:

Given

Let the two forces be

$F_1 = 130N$

$F_2 = 110N$

and

$\tan(\theta) = \frac{12}{5}$

Required

Determine the resultant force

Resultant force (Fr) is calculated using:

$F_r^2 = F_1^2 + F_2^2 + 2F_1F_2\cos(\theta)$

This means that we need to first calculate $\cos(\theta)$

Given that:

$\tan(\theta) = \frac{12}{5}$

In trigonometry:

$\tan(\theta) = \frac{Opposite}{Adjacent}$

By comparing the above formula to $\tan(\theta) = \frac{12}{5}$

$Opposite = 12$

$Adjacent = 5$

The hypotenuse is calculated as thus:

$Hypotenuse^2 = Opposite^2 + Adjacent^2$

$Hypotenuse^2 = 12^2 + 5^2$

$Hypotenuse^2 = 144 + 25$

$Hypotenuse^2 = 169$

$Hypotenuse = \sqrt{169$

$Hypotenuse = 13$

$\cos(\theta)$ is then calculated using:

$\cos(\theta)= \frac{Adjacent}{Hypotenuse}$

$\cos(\theta)= \frac{5}{13}$

Substitute values for $F_1$ , $F_2$ and $cos(\theta)$ in

$F_r^2 = F_1^2 + F_2^2 + 2F_1F_2\cos(\theta)$

$F_r^2 = 130^2 + 110^2 + 2*130*110*\frac{5}{13}$

$F_r^2 = 16900 + 12100 + 11000$

$F_r^2 = 40000$

Take square roots of both sides

$F_r = \sqrt{40000$

$F_r = 200N$

Hence, the resultant force is 200N

4 0

3 years ago