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Elan Coil [88]
2 years ago
6

What information you would gain by watching the video. Plz Help due today.

Engineering
1 answer:
Archy [21]2 years ago
3 0

Answer: It doesnt let me watch the link im sorry :(

Explanation:

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Briefly describe the function of the thermostatic expansion valve in a vapour compression refrigeration system
dalvyx [7]

Answer:

Explanation:

Thermostatic expansion valve is mainly a throttling device commonly used in air conditioning systems and refrigerators.

It is an automatic valve that maintains proper flow of refrigerant in the evaporator according to  the load inside the evaporator. When the load in the evaporator is higher the valve opens and  allows the increase in flow of refrigerant and when the load reduces the valve closes a bit and  reduces the flow of refrigerant. This process leads to higher efficiency of compressor as well as the whole refrigeration system.  Thus TEV works to reduce the pressure of refrigerant from higher condenser pressure to the lower evaporator pressure. It also keeps the evaporator active.      

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3 years ago
What is the locating position of the land field?​
Ivahew [28]

Any point on earth can be located by specifying its latitude and longitude, including Washington, DC, which is pictured here. Lines of latitude and longitude form an imaginary global grid system, shown in Fig. 1.17. Any point on the globe can be located exactly by specifying its latitude and longitude.

4 0
3 years ago
True or False; The Neutrons in an atom have a neutral charge.​
yanalaym [24]

Answer:

true

Explanation:

if it is not true it is false

3 0
3 years ago
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Thick fluids such as asphalt and waxes and the pipes in which they flow are often heated in order to reduce the viscosity of the
Gala2k [10]

Answer:

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7 0
3 years ago
Using the AASHTO procedure, determine the thickness required for a base and a surface layer over existing subgrade. The structur
garri49 [273]

Answer:

<u>the thickness required would be 12 inch HMA and granular base layer of 6 inches</u>

Explanation:

structural number = 4.5

stone base course material coefficient = 0.13

hma material layer coefficient = 0.40

drainage coefficient = 0.90

we will use layered analysis procedure to get thickness

D1 >= sN1/a1

when we cross multiply,

sN1 = a1D1 >=sN1

D2 >= -sN2-sN1/a2m2

sN2* + sN1* >= sN2

D3 >= sN3-(sN1*+sN2*)/a2m2

where a1,a2,a3 = layer coefficient

d1 d2 d3 = actual thickness

m2,m3 = coefficient of base

a1 = 0.4

a1 = 0.13

sN = 4.5

m2 = 0.9

D1 >= sN1/a1 = 4.5/0.4

= 11.25

thickness of surface = 12 inches

a1D1 = 0.4x12 = 4.8

we have value of sN2 = 5.5

(5.5 -4.8)/(0.13*0.9)

= 0.7/0.117

= 5.9829 inches

approximately 6 inches

so the pavement will have 12inch HMA surface and 6 inches granular base layer.

7 0
3 years ago
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