Number of atoms in 1.4 mol of Phosphorus trifluoride (PF₃) : 8.428 x 10²³
<h3>Further explanation </h3>The mole is the number of particles(molecules, atoms, ions) contained in a substance
1 mol = 6.02.10²³ particles
Can be formulated
N=n x No
N = number of particles
n = mol
No = Avogadro's = 6.02.10²³
1.4 mol of Phosphorus trifluoride (PF₃), number of atoms :
Answer:
5.25 moles.
Explanation:
The decomposition reaction of NaN₃ is as follows :
We need to find how many grams of N₂ produced in the process.
From the above balanced chemical reaction, we conclude that the ratio of moles of sodium azide and nitrogen gas are 2 : 3.
2 moles of sodium azide decomposes to give 3 moles of nitrogen gas. So,
3.5 moles of sodium azide decomposes to give moles of nitrogen gas.
Hence, the number of moles produced is 5.25 moles.
