Tin(II)nitride :
Formula Sn₃N₂<span>.
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An acid-base reaction or a neutralization reaction is a <u>chemical reaction that occurs between an acid and a base producing a salt and water</u>. The acids and bases can be strong or weak depending on their degree of ionization in water.
Butyric acid is a weak acid and in water it is ionized in the following way, loosing a proton (H+):
HC4H7O2 (aq) ⇆ H+ (aq) + C4H7O2- (aq)
On the other hand, potassium hydroxide is a strong base, so it will be completely ionized in water:
KOH(aq) → K+(aq) + OH-(aq)
Then the <u>net acid-base reaction</u> between butyric acid and KOH is:
HC4H7O2 (aq) + OH- (aq) ⇆ H2O + C4H7O2- (aq)
It is valid to consider only the OH- produced from the ionization of KOH in water since, as mentioned, this molecule is completely ionized. Also, we do not include the K + in the net equation since it is a spectator ion, it does not undergo chemical changes.
Answer:
The atomic radius corresponds to Sigma
Explanation:
It is the Van Der Waals radius ;)
Answer:
See explanation for detailed solution
Explanation:
The balanced reaction equation is Ba(NO3)2 + 2HSO3NH2 → Ba(SO3NH2)2 + 2HNO3
Number of moles of Ba(NO3)2 = 1.4 g/ 261.337 g/mol = 5.36 × 10^-3 moles
From the reaction equation;
1 mole of Ba(NO3)2 yields 1 mole of Ba(SO3NH2)2
5.36 × 10^-3 moles of Ba(NO3)2 yields 5.36 × 10^-3 moles of Ba(SO3NH2)2
For HSO3NH2
Number of moles = 2.4g/97.10 g/mol =0.0247 moles
2 moles of HSO3NH2 yields 1 mole of Ba(SO3NH2)2
0.0247 moles of HSO3NH2 yields 0.0247 ×1/2 = 0.0137 moles
Hence, Ba(NO3)2 is the limiting reactant
The theoretical yield of Ba(SO3NH2)2 is 5.36 × 10^-3 moles × 329.4986 g/mol = 1.766 g
b)
Number of moles = mass/ molar mass
Molar mass = mass/ number of moles
Molar mass = 1.6925 g/5.36 × 10^-3 moles = 315.76 g
