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ella [17]
3 years ago
12

N2, O2, and CO2 are all contained in a sealed flask. The total pressure of the mixture is 12.5atm. Calculate the partial pressur

e of CO2 if the pressure of N2 is 3.7atm and O2 is 4.8atm.
Chemistry
1 answer:
elena-14-01-66 [18.8K]3 years ago
7 0

Answer:

The partial pressure of C02 is 4 atm

Explanation:

The sum of the partial pressures of the gases that make up a gaseous mixture is equal to the total pressure of said mixture, according to Dalton's law:

P total = P N2 + P 02 + PC02

PC02 = P total -  P N2 - P 02= 12, 5 atm -3, 7 atm -4,8 atm= <em>4 atm</em>

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olasank [31]

Answer: (a) There are 0.428 moles present in 12 g of N_{2} molecule.

(b) There are 2 moles present in 12.044 \times 10^{23} particles of oxygen.

Explanation:

(a). The mass of nitrogen molecule is given as 12 g.

As the molar mass of N_{2} is 28 g/mol so its number of moles are calculated as follows.

No. of moles = \frac{mass}{molar mass}\\= \frac{12 g}{28 g/mol}\\= 0.428 mol

So, there are 0.428 moles present in 12 g of N_{2} molecule.

(b). According to the mole concept, 1 mole of every substance contains 6.022 \times 10^{23} atoms.

Therefore, moles present in 12.044 \times 10^{23} particles are calculated as follows.

Moles = \frac{12.044 \times 10^{23}}{6.022 \times 10^{23}}\\= 2 mol

So, there are 2 moles present in 12.044 \times 10^{23} particles of oxygen.

4 0
3 years ago
Is there a mathematical pattern in the number of
aleksandrvk [35]

Answer:

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Explanation:

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3 years ago
Draw it draw lewis dot structures for each hypothetical molecule shown below, using the correct number of valence electrons for
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The first molecule is a sensible molecule having complete octet of each atom such as C, H and O whereas the second molecule having hydrogen present between the aldehyde and methyl group and thus showing hydrogen is making bond with aldehyde and methyl as well which is not possible because hydrogen only having one electron in its octet due to which it can only form a single bond by sharing its valence electron.

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gavmur [86]

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3 years ago
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