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ella [17]
3 years ago
12

N2, O2, and CO2 are all contained in a sealed flask. The total pressure of the mixture is 12.5atm. Calculate the partial pressur

e of CO2 if the pressure of N2 is 3.7atm and O2 is 4.8atm.
Chemistry
1 answer:
elena-14-01-66 [18.8K]3 years ago
7 0

Answer:

The partial pressure of C02 is 4 atm

Explanation:

The sum of the partial pressures of the gases that make up a gaseous mixture is equal to the total pressure of said mixture, according to Dalton's law:

P total = P N2 + P 02 + PC02

PC02 = P total -  P N2 - P 02= 12, 5 atm -3, 7 atm -4,8 atm= <em>4 atm</em>

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2 years ago
Which is the best example of a new substance forming?
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lighting a match is the answer.

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What is the ph of a 0.25 m solution of c6h5nh2 given that its kb is 1.8 x 10-6?
IrinaK [193]

The pH a 0.25 m solution of C₆H₅NH₂ is equal to 3.13.

<h3>How do we calculate pH of weak base?</h3>

pH of the weak base will be calculate by using the Henderson Hasselbalch equation as:

pH = pKb + log([HB⁺]/[B])

pKb = -log(1.8×10⁻⁶) = 5.7

Chemical reaction for C₆H₅NH₂ is:

                          C₆H₅NH₂ + H₂O → C₆H₅NH₃⁺ + OH⁻

Initial:                     0.25                           0            0

Change:                    -x                             x             x

Equilibrium:        0.25-x                           x             x

Base dissociation constant will be calculated as:
Kb = [C₆H₅NH₃⁺][OH⁻] / [C₆H₅NH₂]

Kb = x² / 0.25 - x

x is very small as compared to 0.25, so we neglect x from that term and by putting value of Kb, then the equation becomes:

1.8×10⁻⁶ = x² / 0.25

x² = (1.8×10⁻⁶)(0.25)

x = 0.67×10⁻³ M = [C₆H₅NH₃⁺]

On putting all these values on the above equation of pH, we get

pH = 5.7 + log(0.67×10⁻³/0.25)

pH = 3.13

Hence pH of the solution is 3.13.

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2 years ago
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For better representation, let me rewrite the electronic configuration:

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