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Mice21 [21]
3 years ago
6

Which equation is equivalent to the formula below?y = a(x – h)^2 + k​

Mathematics
2 answers:
PolarNik [594]3 years ago
8 0

Answer:

See below.

Step-by-step explanation:

The given equation is in vertex form. We can convert it to standard form as follows:

y = a(x - h)^2 + k

y = a(x^2 - 2hx + h^2) + k

y = ax^2 - 2ahx + (ah^2 + k)  (answer).

avanturin [10]3 years ago
3 0

The photo provided by me has the answer attached.

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When Ryan started a daily exercise routine, he lost
Delicious77 [7]
Take his now weight which is 180.4. Divide it by 0.82 because 18% off is 82%. So 180.4/0.82= 220 pounds
7 0
3 years ago
At the beginning of an experiment, the number of bacteria in a colony was counted at time t=O. The number of bacteria in the col
yan [13]

Answer:

1092

Step-by-step explanation:

We have been given that the number of bacteria in the colony t minutes after the initial count modeled by the function B(t)=9(3)^t. We are asked to find the average rate of change in the number of bacteria over the first 6 minutes of the experiment.

We will use average rate of change formula to solve our given problem.

\text{Average rate of change}=\frac{f(b)-f(a)}{b-a}

Upon substituting our given values, we will get:

\text{Average rate of change}=\frac{b(6)-b(0)}{6-0}

\text{Average rate of change}=\frac{9(3)^6-9(3)^0}{6}

\text{Average rate of change}=\frac{9(729)-9(1)}{6}

\text{Average rate of change}=\frac{6561-9}{6}

\text{Average rate of change}=\frac{6552}{6}

\text{Average rate of change}=1092

Therefore, the average rate of change in the number of bacteria is 1092 bacteria per minute.

8 0
3 years ago
Shana ran 6miles in 1 week. this is one third of what she ran in the month. let m represent the number of miles shana ran in a l
Slav-nsk [51]
Let m be the distance (in miles) she runs in a month
and w be the distance (in miles) she runs in a week

since the total distance she run in a week is one third of what she run in a month, in equation form
w = m/3

to calculate the distance she run  in a month,
m = 3w
m = 3(6 miles)
m = 18 miles in a month
6 0
3 years ago
Bob and Doug are both 100-meter sprinters. Bob's sprint time is normally distributed with a mean of 10.00 seconds and Doug's spr
alexdok [17]

Answer:

The standard deviation (σ) = 0.05

Step-by-step explanation:

The question is to find the standard deviation.

STEEP 1: FIND THE MEAN

(10+9.9) ÷ 2 = 9.95

STEP 2: SQUARE THE DIFFERENCE BETWEEN SPRINT TIME AND MEAN

10-9.95= 0.05

0.05^2 = 0.0025

9.9 - 9.95= -0.0025

-0.0025^2 = 0.0025

STEP 3: FIND THE VARIANCE

0.0025+0.0025= 0.005

0.005/2= 0.0025

STEP 4: FIND THE STANDARD DEVIATION (σ )

√variance

√0.0025 = 0.05

Therefore

σ = 0.05.

From the standard deviation, the percentage probability of the higher value to occurs is

0.05×100= 5%

That means Doug has 95%

And Bob has 5%

3 0
3 years ago
11% as a decimal=<br><br> 200% as a decimal=<br> 20.07% as a decimal<br> 198.4% as a decimal
Hitman42 [59]
To convert from a percentage to a decimal, move the decimal twice to the left

11% = 0.11
200% = 2.00
20.07% = 0.2007
198.4% = 1.984

Hope this helps!
8 0
4 years ago
Read 2 more answers
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