Question

A person walks 20.0° north of east for 3.20 km. How far would she have to walk due north and due east to arrive at the same location? ______ km (due north) ___________ km (due east)

Answer 1

Answer:

1.09 km, 3 km

Explanation:

displacement, d = 3.20 km at 20° North of east

A vector quantity has two components one along the x axis and the other is along Y axis. the component along X axis is called the horizontal component and it is due east.

The component along y axis is called vertical component and it is due North.

Displacement due North, dy = 3.20 Sin 20° = 1.09 km

Displacement due east, dx = 3.20 Cos 20° = 3 km