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BabaBlast [244]
3 years ago
14

Question 2 (1 point)

Physics
1 answer:
inysia [295]3 years ago
4 0

Answer:

I think it could be 85 m/s East but go for what you thought of because im not exactly sure.

Explanation:

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What is the shape of a solid?
aleksandrvk [35]

Answer:

3d shape is the shape of solid

6 0
3 years ago
The cost of buying shirts is partly constant and partly varies with the number of shirts bought. When the number of shirts is 5
Jet001 [13]

Answer:

The cost of the buying the shirts is #9680

Explanation:

let the cost of buying shirt = C

let the number of shirt bought = N

The following equation can be generated based on the statement above;

C = k + Nb

When the cost, C = #240, the number of shirt = 5

240 = k + 5b ------ equation (1)

where;

k and b are constants

When the cost, C = #400, the number of shirt = 10

400 = k + 10b ------ equation (2)

From equation (1), make k the subject of the formula;

k = 240 - 5b ---- equation (3)

Substitute in the value of k into equation (2)

400 = k + 10b

400 = (240 - 5b) + 10b

400 = 240 - 5b + 10b

400 - 240 = -5b + 10b

160 = 5b

b = 160 / 5

b = 32

From equation (3), calculate k

k = 240 - 5b

k = 240 -5(32)

k = 240 - 160

k = 80

When the number of shirts bought = 300, the cost of the buying the shirts =

C =  k + Nb

C = 80 +32N

Where;

N is the number of shirts

C = 80 + 32(300)

C = 80 + 9600

C = #9680

Therefore, the cost of the buying the shirts is #9680

8 0
3 years ago
How much energy is stored in a spring with a spring constant of 390 N/m if the spring is compressed a distance of 0.45 m from it
masya89 [10]
F=-ks
F=-(390)(.45)
F=-175.5 N

Work=force x displacement
Work= 175.5(0.45)
Work= 78.98 J

Work = ∆E =78.98 J

Answer=79J (first option)
4 0
3 years ago
Name two examples of deposition.
Rashid [163]
The reverse of deposition is sublimation and hence sometimes deposition is called desublimation. One example of deposition is the process by which, in sub-freezing air, water vapor changes directly to ice without first becoming a liquid.
8 0
4 years ago
Read 2 more answers
a thundercloud whose base is 500m above the ground. The potential difference between the base of the cloud and the m ground is 2
kolezko [41]

Answer:

1.6×10⁻⁶ N.

Explanation:

From the question,

F = (V/r)q......................... Equation 1

Where F = Electric force on the raindrop, V = Potential difference between the base of the cloud and the ground, r = distance between the base of the cloud and the ground, q = the charge on a rain drop.

Given: V = 200MV = 200×10⁶ V, r = 500 m, q = 4.0×10⁻¹² C.

Substitute these values into equation 1

F = [(200×10⁶ )/500]×4.0×10⁻¹²

F = 1.6×10⁻⁶ N.

3 0
3 years ago
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