Question 2 (1 point)
1 answer:
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Answer:
The speed of the big fish after swallowing the small fish is 0.38 m/s.
Explanation:
Consider west to east direction as positive and the opposite direction as negative.
Given:
Mass of big fish (m₁) = 12.0 kg
Initial velocity of big fish (u₁) = 75 cm/s = 0.75 m/s
Mass of small fish (m₂) = 1 kg
Initial velocity of small fish (u₂) = -4 m/s (Direction is opposite to u₁)
After swallowing the small fish, both the fishes move together with same velocity. Let the velocity be 'v'.
So, as there are no effects of drag or any other forces, the given scenario can be considered as a case of inelastic collision where the objects move together with same velocity after collision.
The momentum is conserved in inelastic collision. Therefore,
Initial momentum of the fishes = Final momentum of the fishes
Now, plug in the given values and solve for 'v'. This gives,
Therefore, the speed of the big fish after swallowing the small fish is 0.38 m/s
Answer:
82.1 km
Explanation:
We need to resolve each displacement along two perpendicular directions: the east-west direction (let's label it with x) and the north-south direction (y). Resolving each vector:
Vector B is 48 km south, so:
Finally, vector C:
Now we add the components along each direction:
So, the resultant (which is the distance in a straight line between the starting point and the final point of the motion) is
Answer:
The final pressure of the gas is 9.94 atm.
Explanation:
Given that,
Weight of argon = 0.16 mol
Initial volume = 70 cm³
Angle = 30°C
Final volume = 400 cm³
We need to calculate the initial pressure of gas
Using equation of ideal gas
Where, P = pressure
R = gas constant
T = temperature
Put the value in the equation
We need to calculate the final temperature
Using relation pressure and volume
Hence, The final pressure of the gas is 9.94 atm.