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rusak2 [61]
2 years ago
7

6. If two objects each have a mass of 10 kg, then the force of gravity between them

Physics
1 answer:
frozen [14]2 years ago
8 0

Answer:

3

Explanation:

Answer is what its supposed to be. lol.

Stick with it brother. You GOT THIS!!! 100%

b.

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Photo shows all! Need help ASAP! Will mark brainlist
Goryan [66]

Answer:

The student is getting different info bc the students probable keeping track of the distance instead of the displacement.

Explanation:

5 0
3 years ago
Can you ever absolutely prove that a hypothesis is correct? Explain.
Diano4ka-milaya [45]

Yes you can, with using scientific experiment.

Ask a question -- Do background Research -- Construct a Hypothesis --Test with an Experiment -- Procedure working? -- Yes or no? -- Analyze Data and Draw Conclusions

With an experiment you can discover if its correct or not.

Hope this helps ! <3

8 0
3 years ago
Racing greyhounds are capable of rounding corners at very high speeds. A typical greyhound track has turns that are 45 m diamete
Readme [11.4K]

Answer:

In m/s^2:

a=11.3778 m/s^2

In units of g:

a=1.161 g

Explanation:

Since the racing greyhounds are capable of rounding corners at very high speed so we are going use the following formula of acceleration for circular paths.

a=\frac{v^2}{r}

where:

v is the speed

r is the radius

Now,

a=\frac{16^2}{45/2}\\ a=11.3778 m/s^2

In g units:

a=\frac{11.3778\ g}{9.8}\\ a=1.161\ g

7 0
3 years ago
A colloidal liquid in a has is called
S_A_V [24]
Aerosol is the answer
8 0
3 years ago
A shell is fired from the ground with an initial speed of 1.60 × 103 m/s (approximately five times the speed of sound) at an ini
Volgvan

Answer:

The horizontal range will be 2.55\times 10^5m

Explanation:

We have given initial speed of the shell u = 1.6\times 10^3m/sec

Angle of projection = 51°

Acceleration due to gravity g=9.8m/sec^2

We have to find maximum range

Horizontal range in projectile motion is given by

R=\frac{u^2sin2\Theta }{g}=\frac{(1.60\times 10^3)^2sin(2\times 51^{\circ})}{9.81}=2.55\times 10^5m

So the horizontal range will be 2.55\times 10^5m

6 0
3 years ago
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