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Novay_Z [31]
3 years ago
8

Small paragraph explaining how how potential and kinetic energy are related

Physics
2 answers:
ch4aika [34]3 years ago
7 0
Kinetic energy is the energy of a moving object. Potential energy is the energy an object CAN have. For example a ball about to be dropped has potential energy. They are related because when an object has potential energy, once put into motion, it uses kinetic energy to move, and when it stops, it has potential energy. It’s kind of like a cycle.
weeeeeb [17]3 years ago
4 0

Answer:

Kinetic energy is energy possessed by a body by virtue of its movement. Potential energy is the energy possessed by a body by virtue of its position or state. While kinetic energy of an object is relative to the state of other objects in its environment, potential energy is completely independent of its environment.

Explanation:

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A sample of oxygen gas with a volume of 3.0 m3 is at 100 C. The gas is heated so that
vesna_86 [32]

\qquad\qquad\huge\underline{{\sf Answer}}

According to Charles law, if pressure remains constant, volume varies directly with temperature. so we can infer that :

\qquad\sf{\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}}

So, we can use this formula to find out the final temperature of the gas ~

Note : Take temperature in Kelvin ( 100°C = 373 K )

\qquad \sf  \dashrightarrow \:  \dfrac{3}{373}  =  \dfrac{6}{x}

\qquad \sf  \dashrightarrow \: x =  \dfrac{6}{3} \times 373

\qquad \sf  \dashrightarrow \: x = 2 \times 373

\qquad \sf  \dashrightarrow \: x =74 6 \: K

Now, convert it to Celsius ~

i.e 746 - 273 = 473° C

So, the final temperature of the gas will be equal to 473° C

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2 years ago
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Un globo aerostático asciende con velocidad constante de 2.45 m/s. Cuando el globo aerostático está subiendo y se encuentra a 35
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A cord is wrapped around the outer surface of the 8-kg disk. If a force of F = (1⁄4u2) N, where u is in radians, is applied to t
Soloha48 [4]

A cord is wrapped around the outer surface of the 8-kg disk. If a force of F = (1⁄4θ²) N, where θ is in radians, is applied to the cord, determine the disk’s angular acceleration when it has turned 5 revolutions. The disc has an initial angular velocity \omega _o = 1 \ rad/s and radius from the center of the disc = 300 mm

Answer:

the angular acceleration = 205.706 rad/sec²

Explanation:

GIVEN THAT:

The disc mass = 8 kg

Force = \dfrac{1}{4} \ \ \theta ^2* N

We are told that the given θ is in radians; Therefore; the when it has turned 5 revolutions; we have the θ to be:

\theta = 5 rev * (\dfrac{2 \  \pi  * rad}{1 rev}) \\ \\ \theta = 10 \ \pi \ rad

Also;

the initial angular velocity \omega _o = 1 \ rad/s

radius from the center of the disc = 300 mm = 0.3 m

Thus; the mass moment about the Inertia can be determined via the following expression;

I_o = \dfrac{1}{2}*m*r^2

I_o = \dfrac{1}{2}*8*0.3^2

I_o = 0.36 \ kg/m^3

Now to calculate the angular acceleration; we equate the sum of the moments acting on the Inertia;

SO:

\sum M_o = I_o \alpha

F*0.3 = 0.36* \alpha

\dfrac{1}{2}* \theta^2 *0.3 = 0.36* \alpha

\alpha = 0.20836 \  \theta^2 \ rad/sec^2

\alpha = 0.20836 \  (10 \ \pi )^2 \ rad/sec^2

\alpha = 205.706 \ rad/sec^2

Hence; the angular acceleration = 205.706 rad/sec²

6 0
3 years ago
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