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avanturin [10]
3 years ago
8

What is the solution to y=5x-7 -3x-2y=-12

Mathematics
2 answers:
poizon [28]3 years ago
7 0
Since <span>−3x</span><span> does not contain the </span>variable<span> to solve for, move it to the right-hand side of the </span>equation<span> by adding </span><span>3x</span><span> to both sides.
</span><span>y=5x−7</span> 
<span>−2y=3x−12

</span>Divide<span> each </span>term<span> in the </span>equation<span> by </span><span><span>−2</span>.
</span><span>y=5x−7</span> 
<span>y=−<span><span>3x/</span>2</span>+6

</span>Create a graph<span> to locate the </span>intersection<span> of the </span>equations<span>. The </span>intersection<span> of the </span><span>system of equations</span><span> is the </span>solution<span>.
</span>
<span>(2,3)
</span>

likoan [24]3 years ago
4 0
y=5x-7 \\&#10;-3x-2y=-12 \\ \\&#10;\hbox{substitute 5x-7 for y in the 2nd equation:} \\&#10;-3x-2(5x-7)=-12 \\&#10;-3x-10x+14=-12 \\&#10;-13x+14=-12 \ \ \ |-14 \\&#10;-13x=-26 \ \ \ |\div (-13) \\&#10;x=2 \\ \\&#10;y=5x-7=5 \times 2-7=10-7=3 \\ \\&#10;\boxed{(x,y)=(2,3)}
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Answer:

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Step-by-step explanation:

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we are have to know for which value or input units are these functions at maximum which translates to for how many units is the revenue maximum and for how many same units is our cost minimum.

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4 years ago
What is the quotient of -8(^6)/4x(^-3)
Anna [14]

For this case we must find the quotient of the following expression:

\frac {-8x ^ 6} {4x ^ {- 3}} =

By definition of power properties we have:

a ^ {- 1} = \frac {1} {a ^ 1} = \frac {1} {a}

Rewriting the expression we have:

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8 0
4 years ago
Which equation is graphed in the diagram below ​
Deffense [45]

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Step-by-step explanation:

7 0
3 years ago
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7 0
3 years ago
6a-2(4a-5)=40<br>How do I solve it​
Elza [17]

Answer:

Distribute, then combine like terms, subtract 10 from both sides of the equation, simplify, divide both sides of the equation by the same term, and simplify to get your solution.

Step-by-step explanation:

1.) Distribute

6−2(4−5)=40

6−8+10=40

2.) Combine like terms

6a-8a+10=40

-2a+10=40

3.) Subtract 10 from both sides of the equation

-2a+10=40

-2a+10-10=40-10

4.) Simplify

subtract the numbers

-2a+10-10=40-10

-2a=40-10

subtract the numbers

-2a=40-10

-2a=30

-2a=30

5.) Divide both sides of the equation by the same term

-2a=30

\frac{-2a}{-2} =\frac{30}{-2}

6.) Simplify

cancel terms that are in both the numerator or denominator

\frac{-2a}{-2} =\frac{30}{-2}

a=\frac{30}{-2}

Divide the numbers

a=\frac{30}{-2}

a=-15

a=-15

7.) Solution

a=-15

8 0
3 years ago
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