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Aleks [24]
3 years ago
10

E=300-10 (30) How to solve it step by step

Mathematics
1 answer:
Zepler [3.9K]3 years ago
6 0

Answer:

Step-by-step explanation:

e = 300-10(30)

e = 300 - 300

e = 0

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A map has a scale of 5 in. = 15 mi. If you measured the distance between two cities to be 26 in. On the map, how many miles woul
Reil [10]

Answer:

Actual distance between the two cities given on the map = 78.0 miles

Step-by-step explanation:

Scale used for the actual distance between two cities on a map is,

5 in. = 15 mi.

\frac{5}{15} in. = \frac{15}{15} mi.

1 mi. = \frac{1}{3} in.

1 inch = 3 miles

Therefore, 26 inches on the map = 26 × 3

                                                        = 78 miles

Therefore, actual distance between the two cities given on the map = 78.0 miles

5 0
2 years ago
Can someone plsss help me?!
MAXImum [283]

Answer:

Angle A is 101

Angle B is 79

Angle C is 83

Angle D is 97

Step-by-step explanation:

Vertical angles are congruent, which applies to C.

Lines are parallel so 79 and angle B are the same

Angle a is 101 because its a supplementary angle

Angle D is 97 because its also a supplementary angle so you subtract 83 from 180.

3 0
2 years ago
Which equation could be used to solve for the measure of side Q in the triangle QRS shown below given...
Rama09 [41]

The image is missing, so i have attached it

Answer:

Equation is;

q/sin 105 = 15/sin 30

Step-by-step explanation:

We are given;

Angle Q = 105°

Angle S = 30°

s = 15

From sine rule we know that;

a/sin A = b/sin B = c/sin C.

Thus, applying that to this question, we can find side q.

Thus;. q/Sin Q = s/Sin S

Plugging in the relevant values to obtain ;

q/sin 105 = 15/sin 30

8 0
2 years ago
Yesterday Mike bought 2 gallons of regular gasoline and 3 gallons of premium gasoline at a gas station for $13.60 today he bough
larisa [96]

Answer:

Cost of 1 gallon of Regular gasoline is $2.45 and  Cost of 1 gallon of Premium gasoline is $2.90.

Step-by-step explanation:

Let the Cost of Regular gasoline be 'x'.

Let the Cost of Premium gasoline be 'y'.

Given:

Amount of regular gasoline bought yesterday = 2 gallons

Amount of premium gasoline bought yesterday = 3 gallons

Total Cost of yesterday = $13.60

Now we know that Total Cost of yesterday is equal to sum of Amount of regular gasoline bought yesterday multiplied by Cost of Regular gasoline and Amount of Premium gasoline bought yesterday multiplied by Cost of premium gasoline.

Framing in equation form we get;

2x+3y=13.60 \ \ \ \ equation\ 1

Also Given:

Amount of regular gasoline bought today = 3 gallons

Amount of premium gasoline bought Today = 4 gallons

Total Cost of Today = $18.95

Now we know that Total Cost of Today is equal to sum of Amount of regular gasoline bought Today multiplied by Cost of Regular gasoline and Amount of Premium gasoline bought Today multiplied by Cost of premium gasoline.

Framing in equation form we get;

3x+4y=18.95 \ \ \ \ equation\ 2

Now Multiplying equation 1 by 3 we get;

2x+3y=13.60\\\\3(2x+3y)=13.60\times3\\\\6x+9y= 40.80 \ \ \ \ \ equation\ 3

Now Multiplying equation 2 by 2 we get;

3x+4y=18.95\\\\2(3x+4y)=18.95\times2\\\\6x+8y= 37.90 \ \ \ \ \ \ equation\ 4

Subtracting equation 4 from equation 3 we get;

(6x+9y)- (6x+8y)= 40.80-37.90\\\\6x+9y-6x-8y= 2.9\\\\y=\$2.90

Substituting the value of y in equation 1 we get;

2x+3y=13.60\\\\2x+3\times2.90 =13.60\\\\2x+8.7=13.6\\\\2x=13.6-8.7\\\\2x=4.9\\\\x=\frac{4.9}{2} =\$2.45

Hence Cost of 1 gallon of Regular gasoline is $2.45 and  Cost of 1 gallon of Premium gasoline is $2.90.

4 0
3 years ago
The image shown has two triangles sharing a vertex:
Semmy [17]
D. y, because Triangle JHK is similar to triangle LMK
3 0
3 years ago
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