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3 years ago

B=-7+29 show work integers

Mathematics

2 answers:

aivan3 [116]3 years ago

8 0

B is equal to is twenty-two

Mumz [18]3 years ago

6 0

You just add -7 to 29 and it would pretty much be like subtracting it so your answer is 22
B=22
i hope this helps have a nice night

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Rachael scored 12 points

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3 years ago

Question 29: In a club of 35 boys and 28 girls, 80% of the boys and 25% of the girls have been members for more than 2 years. If

klasskru [66]

Answer:

55%

Step-by-step explanation:

What we must do is get the total number of people, that is, boys and girls who have been a member for more than 2 years, that is:

children: 0.8 * 35 = 28

girls = 0.25 * 28 = 7

Now, passing knowing the%, would be dividing the sum of the above by the sum of the total club members:

(28 +7) / (35 + 28) = 0.55

Since it is a number below 1, it cannot be a mixed number.

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3 years ago

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I will give you branilest!

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3 years ago

The perimeter of a rectangular field is 350m. If the length of the field is 99m, what is it’s width?

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Answer:

The width of the field is 3.535353535m

Step-by-step explanation:

350÷99=3.535353535

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3 years ago

A Confidence interval is desired for the true average stray-load loss mu (watts) for a certain type of induction motor when the

Vaselesa [24]

Answer:

A sample size of 35 is needed.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.95}{2} = 0.025$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.025 = 0.975$ , so $z = 1.96$

Now, find the width W as such

$W = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

How large must the sample size be if the width of the 95% interval for mu is to be 1.0:

We need to find n for which W = 1.

We have that $\sigma^{2} = 9$ , then $\sigma = \sqrt{\sigma^{2}} = \sqrt{9} = 3$ . So

$W = z*\frac{\sigma}{\sqrt{n}}$

$1 = 1.96*\frac{3}{\sqrt{n}}$

$\sqrt{n} = 1.96*3$

$(\sqrt{n})^2 = (1.96*3)^{2}$

$n = 34.57$

Rounding up

A sample size of 35 is needed.

3 0

3 years ago