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navik [9.2K]
3 years ago
12

Is it possible to add chemical formulas .

Chemistry
2 answers:
TEA [102]3 years ago
7 0
I agree, yes you can. 

and again, it depends on what for! :)

I really hope this helps you. :)
Zanzabum3 years ago
6 0
Yes you can but for what ?? That depends !

Hope this helps !

Photon
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which statement is true about a molecule? a) a molecule is identical to the component elements. b) a molecule retains the physic
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A molecule retains the chemical properties of the component element.
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2. When do chemical reactions happen?
Alenkinab [10]
Either the 1or3answer
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A plane has a cruising speed of 100 miles per hour when there is no wind. At this speed, the plane flew 600 miles with the wind
alina1380 [7]
The solution for this problem is:
Let x = speed of wind

Speed of plane with the wind = x + 100

Speed of plane against the wind = 100 -x 

 We will be using the formula for distance which is (Rate)(Time), getting the formula for time would be distance/rate Time to travel 600 miles with the wind = Time to travel 400 miles against the wind 600/(x + 100) = 400/(100 - x)

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 400x + 40000 = 60000 - 600x

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8 0
3 years ago
What is the hybridization of the nitrogen atom in ammonia?
dybincka [34]

The nitrogen atom in NH3 is sp3 hybridized. ... In NH3 molecule, three of the sp3 orbitals are used to formbonds to the three hydrogen atoms and the fourth sp3 orbital is used to hold the lone pair. and is sometimes called a non-bonding pair.

6 0
3 years ago
Consider the following reaction where K. = 154 at 298 K: 2NO(g) + Brz(9) 2NOBr(g) A reaction mixture was found to contain 2.69x1
bekas [8.4K]

Explanation:

2NO(g) + Br_2(g)\rightleftharpoons 2NOBr(g)

Equilibrium constant of reaction = K=154

Concentration of NO = [NO]=\frac{2.69\times 10^{-2} mol}{1 L}=2.69\times 10^{-2} M

Concentration of bromine gas = [Br_2]=\frac{3.85\times 10^{-2} mol}{1 L}=3.85\times 10^{-2} M

Concentration of NOBr gas = [Br_2]=\frac{9.56\times 10^{-2} mol}{1 L}=9.56\times 10^{-2} M

The reaction quotient is given as:

Q=\frac{[NOBr]^2}{[NO]^2[Br_2]}=\frac{(9.56\times 10^{-2} M)^2}{(2.69\times 10^{-2} M)^2\times 3.85\times 10^{-2} M}

Q=328.06

Q>K

The reaction will go in backward direction in order to achieve an equilibrium state.

1. In order to reach equilibrium NOBr (g) must be produced.  False

2. In order to reach equilibrium K must decrease. False

3. In order to reach equilibrium NO must be produced. True

4. Q. is less than K . False

5. The reaction is at equilibrium. No further reaction will occur. False

8 0
3 years ago
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