Molal concentration gives the number of moles dissolved in 1 kg of solution.
Molal concentration of H₂SO₄ is 2.88 mol/kg
the weight of H₂SO₄ in 1 kg - 2.88 mol x 98 g/mol = 282.2 g
The total weight of solution - 1000 g + 282.2 g = 1282.2 g
density of solution is 1.167 g/ml
We need to find how many moles are dissolved in 1 L.
We know the weight of the solution, using this we can calculate volume of the solution
volume of solution is - 1282.2 g / 1.167 g/mL = 1098.7 mL
The number of H₂SO₄ moles in 1.0987 L = 2.88 mol
Therefore in 1 L = 2.88 mol / 1.0987 L = 2.62 mol
Molarity of H₂SO₄ is 2.62 mol/L = 2.62 M
Answer:
4) It disrupts the normal excretion of solid wastes.
Explanation:
As it is given that solubility of water in diethyl ether is 1.468 %. This means that in 100 ml saturated solution water present is 1.468 ml.
Hence, amount of diethyl ether present will be calculated as follows.
(100ml - 1.468 ml)
= 98.532 ml
So, it means that 98.532 ml of diethyl ether can dissolve 1.468 ml of water.
Hence, 23 ml of diethyl ether can dissolve the amount of water will be calculated as follows.
Amount of water =
= 0.3427 ml
Now, when magnesium dissolves in water then the reaction will be as follows.
Molar mass of Mg = 24.305 g
Molar mass of = 18 g
Therefore, amount of magnesium present in 0.3427 ml of water is calculated as follows.
Amount of Mg =
= 0.462 g