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-BARSIC- [3]
3 years ago
5

Heat is transferred by conduction through a wall of thickness 0.87 m. What is the rate of heat transfer if the walls thermal con

ductivity is 13 W/m-K, the surface area is 5 m2, and the surface temperatures are 14 °C and 93 °C. Report your answer in Watts.
Chemistry
1 answer:
erik [133]3 years ago
4 0

Explanation:

The given data is as follows.

         Thickness (dx) = 0.87 m,       thermal conductivity (k) = 13 W/m-K

        Surface area (A) = 5 m^{2},       T_{1} = 14^{o}C

        T_{2} = 93^{o}C

According to Fourier's law,

                    Q = -kA \frac{dT}{dx}

Hence, putting the given values into the above formula as follows.

                      Q = -kA \frac{dT}{dx}

                          = -13 W/m-k \times 5 m^{2} \times \frac{(14 - 93)}{0.87 m}

                          = 5902.298 W

Therefore, we can conclude that the rate of heat transfer is 5902.298 W.

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user100 [1]
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7 0
2 years ago
Calculate the final molarity of HCl the resulting solution when 5.56 mL of 4.108 M HCl is added to 4.44 mL of water.
puteri [66]

The final molarity of HCl is 2.284 M

We'll begin by listing what was given from the question. This is shown below:

Initial volume (V₁) = 5.56 mL

Initial Molarity (M₁) = 4.108 M

Final volume (V₂) = 5.56 + 4.44 = 10 mL

<h3>Final Molarity (M₂) =? </h3>

The final molarity of the HCl solution can be obtained by using the dilution formula as illustrated below:

<h3>M₁V₁ = M₂V₂</h3>

4.108 × 5.56 = M₂ × 10

22.84048 = M₂ × 10

Divide both side by 10

M₂ = 22.84048 / 10

<h3>M₂ = 2.284 M</h3>

Therefore, final molarity of the HCl solution is 2.284 M.

Learn more: brainly.com/question/6103588

5 0
2 years ago
Some hypothetical alloy is composed of 12. 5 wt% of metal a and 87. 5 wt% of metal b. If the densities of metals a and b are 4.
gavmur [86]

Answer:

The number of

atoms in the unit cell is 2

Explanation:

7 0
2 years ago
The K w for water at 0 ∘ C is 0.12 × 10 − 14 . Calculate the pH of a neutral aqueous solution at 0 ∘ C.
dusya [7]

Answer:

pH = 7.46

Explanation:

2H₂O  ⇄  H₃O⁺  .  OH⁻          Kw = [H₃O⁺] . [OH⁻]

[H₃O⁺] = [OH⁻]

√0.12×10⁻¹⁴ = [H₃O⁺] → 3.46×10⁻⁸  M

- log  [H₃O⁺] = pH

- log 3.46×10⁻⁸ = pH → 7.46

6 0
3 years ago
How many moles of I(iodine)2 are there in a 500.0g bottle? Please include significant figures
dolphi86 [110]

Answer:

Number of moles = 1.97 mol

Explanation:

Given data;

Number of moles of I₂ = ?

Mass = 500.0 g

Solution:

Number of moles = mass/ molar mass

Molar mass of  I₂ = 253.8 g/mol

Number of moles = 500 g / 253.8 g/mol

Number of moles = 1.97 mol

4 0
3 years ago
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