Question

Heat is transferred by conduction through a wall of thickness 0.87 m. What is the rate of heat transfer if the walls thermal conductivity is 13 W/m-K, the surface area is 5 m2, and the surface temperatures are 14 °C and 93 °C. Report your answer in Watts.

Answer 1

Explanation:

The given data is as follows.

         Thickness (dx) = 0.87 m,       thermal conductivity (k) = 13 W/m-K

        Surface area (A) = 5 $m^{2}$,       $T_{1} = 14^{o}C$

        $T_{2} = 93^{o}C$

According to Fourier's law,

                    Q = $-kA \frac{dT}{dx}$

Hence, putting the given values into the above formula as follows.

                      Q = $-kA \frac{dT}{dx}$

                          = $-13 W/m-k \times 5 m^{2} \times \frac{(14 - 93)}{0.87 m}$

                          = 5902.298 W

Therefore, we can conclude that the rate of heat transfer is 5902.298 W.