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GarryVolchara [31]
3 years ago
9

Using the reactivity series of metals, classify which would be the cathode in a reaction involving these two metals as electrode

s.
Na or Ca?

Chemistry
2 answers:
Georgia [21]3 years ago
8 0

Answer: Na or Ca?

Explanation:

babymother [125]3 years ago
4 0

Answer:

Calcium will be the anode and sodium will be the cathode

Explanation:

I know that your confusion stems from the relative positions of the two metals in the activity series but I want you to get something clearly. Sodium metal is more reactive than calcium metal but calcium ion is more reactive (a better reducing agent) than the sodium ion.

Hence, in an electrochemical cell, a better reducing agent will function as the anode. This is why calcium is the anode in the cell mentioned in the question. Calcium ion has a reduction potential of -2.87 V while sodium ion has a reduction potential of -2.71 V, hence the answer.

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ycow [4]

<u>Answer:</u> For the given equation, only iron has the value of \Delta H_f equal to 0 kJ.

<u>Explanation:</u>

Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. It is represented as \Delta H^o

The equation used to calculate enthalpy change is of a reaction is:

\Delta H^o_{rxn}=\sum [n\times \Delta H^o_f(product)]-\sum [n\times \Delta H^o_f(reactant)]

For the given chemical reaction:

3CO(g)+2Fe_2O_3(s)\rightarrow Fe(s)+3CO_2(g)

The equation for the enthalpy change of the above reaction is:

\Delta H^o_{rxn}=[(1\times \Delta H^o_f_{(Fe(s))})+(3\times \Delta H^o_f_{(CO_2(g))})]-[(3\times \Delta H^o_f_{(CO(g))})+(2\times \Delta H^o_f_{(Fe_2O_3(s))})]

The enthalpy of formation for the substances present in their elemental state is taken as 0.

Here, iron is present in its elemental state which is solid.

Hence, for the given equation, only iron has the value of \Delta H_f equal to 0 kJ.

7 0
3 years ago
Please help which one is it
creativ13 [48]

Answer:

d:more dense and falls

Explanation:

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6 0
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bogdanovich [222]

Answer:

\boxed{\text{pH = 5.00}}

Explanation:

Step 1. Calculate the pOH

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pOH =-log(1.0 × 10⁻⁹)

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Step 2. Calculate the pH

pH + pOH = 14.00

pH + 9.00 = 14.00

\boxed{\textbf{pH = 5.00}}

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Answer:

By bonding due to the attractive forces

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Science is a body of knowledge and process of gaining new knowledge, It is also falsifiable.

Pseudoscience does not follow the scientific process. And it is also unfalsifiable.
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