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GarryVolchara [31]
3 years ago
9

Using the reactivity series of metals, classify which would be the cathode in a reaction involving these two metals as electrode

s.
Na or Ca?

Chemistry
2 answers:
Georgia [21]3 years ago
8 0

Answer: Na or Ca?

Explanation:

babymother [125]3 years ago
4 0

Answer:

Calcium will be the anode and sodium will be the cathode

Explanation:

I know that your confusion stems from the relative positions of the two metals in the activity series but I want you to get something clearly. Sodium metal is more reactive than calcium metal but calcium ion is more reactive (a better reducing agent) than the sodium ion.

Hence, in an electrochemical cell, a better reducing agent will function as the anode. This is why calcium is the anode in the cell mentioned in the question. Calcium ion has a reduction potential of -2.87 V while sodium ion has a reduction potential of -2.71 V, hence the answer.

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Calculate the amount of heat necessary to raise the temperature of 135.0 g of water from 50.4°F to 85.0°F. The specific heat of
MAXImum [283]

Here we have to calculate the heat required to raise the temperature of water from 85.0 ⁰F to 50.4 ⁰F.

10.857 kJ heat will be needed to raise the temperature from 50.4 ⁰F to 85.0 ⁰F

The amount of heat required to raise the temperature can be obtained from the equation H = m×s×(t₂-t₁).

Where H = Heat, s  =specific gravity = 4.184 J/g.⁰C, m = mass = 135.0 g, t₁ (initial temperature) = 50.4 ⁰F or 10.222 ⁰C and t₂ (final temperature) = 85.0⁰F or 29.444 ⁰C.

On plugging the values we get:

H = 135.0 g × 4.184 J/g.⁰C×(29.444 - 10.222) ⁰C

Or, H = 10857.354 J or 10.857 kJ.

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6 0
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What is the bond angle in a tetrahedral molecule?
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109.5

tetrahedral shape:
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7 0
4 years ago
Read 2 more answers
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