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3 years ago

Estimate the heat released when ethene (CH2=CH2) reacts with HBr to give CH3CH2Br.

Chemistry

1 answer:

bonufazy [111]3 years ago

7 0

Answer:

Explanation:

The reaction between ethene and HBr is:

CH2=CH2 + HBr → CH3CH2Br

Thus, the double bond C=C and the bond H-Br were broken, and the bonds C-C, C-H and C-Br were formed. The enthalpy of the reaction (the energy change), is the sum of the enthalpies of the reactions that were broken with the bonds that were created.

To break a bond, it's necessary to the molecule to gain energy, thus the process is endothermic and H>0, and to form a bond, it's necessary to release energy, and so H<0, so:

ΔH = ∑n*Hbroken - ∑n*Hformed, where n is the coefficient of the substance, so:

ΔH = (612 + 366) - (348+412+276)

ΔH = -58 kJ/mol

The minus signal indicates that the energy was released.

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Answer:

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ee = |A-B|/ A+B * 100

ee = |98%-2%| / 98+2 * 100

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2 years ago

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2 years ago

Prepare 10.00 mL of 0.010 M NaOH by diluting the NaOH solution used in Trial 1. (Your procedure should clearly show your calcula

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Answer:

= 0.2 mL.

Explanation:

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$C_{1} V_{1} = C_{2} V_{2}$

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I hope this was a detailed explanation given the missing details of "Trial 1" in the question.

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