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pantera1 [17]
3 years ago
15

Select the two elements isolated by the Curies.

Chemistry
2 answers:
ss7ja [257]3 years ago
7 0

The right options are; radium and polonium

The two elements isolated by the Curies are; radium and polonium.

Marie and Pierre Curie discovered the existence of the elements radium and polonium when they conducted pioneering research on radioactivity. They successfully removed radioactive radium salts from the mineral pitchblende in their laboratory. Marie Curie also discovered that the potential to emit radiation does not rely on the structural arrangement of the atoms in a molecule.

Mkey [24]3 years ago
5 0
Radium and polonium is the answer to this question. I hope I helped out!
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What is the mass of KOH found in a 785 mL of a 1.43 M solution of KOH
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Molarity is defined as the ratio of number of moles to the volume of solution in litres.

The mathematical expression is given as:

Molarity = \frac{Number of moles}{volume of solution in litres}

Here, molarity is equal to 1.43 M and volume is equal to 785 mL.

Convert mL into L

As, 1 mL = 0.001 L

Thus, volume = 785\times 0.001 = 0.785 L

Rearrange the formula of molarity in terms of number of moles:

Number of moles =molarity\times volume of solution in litres

n = 1.43 M \times 0.785 L

= 1.12255 mole

Now,  Number of moles  = \frac{mass in g}{molar mass}

Molar mass of potassium hydroxide  = 56.10 g/mol

1.12255 mole  = \frac{mass in g}{56.10 g/mol}

mass in g = 1.12255 mole\times 56.10 g/mol

= 62.97 g

Hence, mass of KOH = 62.97 g



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