Answer:
The displacement of the train in this time period is 2,616.86 m.
Explanation:
A Uniformly Varied Rectilinear Motion is Rectilinear because the mobile moves in a straight line, Uniformly because of there is a magnitude that remains constant (in this case the acceleration) and Varied because the speed varies, the final speed being different from the initial one.
In other words, a motion is uniformly varied rectilinear when the trajectory of the mobile is a straight line and its speed varies the same amount in each unit of time (the speed is constant and the acceleration is variable).
An independent equation of useful time in this type of movement is:
<em>Expression A</em>
where:
- vf = final velocity
- vi = initial velocity
- a = acceleration
- d = distance
The equation of velocity as a function of time in this type of movement is:
vf=vi + a*t
So the velocity can be calculated as: 
In this case:
- vf=42.4 m/s
- vi=27.5 m/s
- t=75 s
Replacing in the definition of acceleration: 
a=0.199 m/s²
Now, replacing in expression A:
Solving:
d= 2,616.86 m
<u><em>The displacement of the train in this time period is 2,616.86 m.</em></u>
The youngest age that this person can be and legally operate a boat powered by a motor of more than 35 hp will be 12 years of age.
<h3 /><h3>What is electric power?</h3>
It is the rate of the electric work done. Its unit is the watt. Horsepower is the unit of power.
A person under the age of 12 may only legally operate a boat with a motor that has more than 6 horsepower but no more than 35 horsepower
if they meet two requirements: they have a boating safety certificate, which they must have on board; and they are being closely watched by an adult who is at least 16 years old.
Hence the youngest age that this person can be and legally operate a boat powered by a motor of more than 35 hp will be 12 years of age.
To learn more about electric power refer to the link;
brainly.com/question/12316834?referrer=searchResults
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<span>5.3 cm/s
This is a matter of conservation of momentum. Since there's no mention of the puck rebounding, I will consider this to be a totally non-elastic collision. So, let's determine the starting momentum of the system.
Goalie is at rest, so his momentum is 0.
Puck is moving at 30.00 m/s with a mass of 0.16 kg, so:
30.00 m/s * 0.16 kg = 4.8 kg*m/s
So the starting momentum is 4.8 kg*m/s moving towards the goal. After the collision, the puck and goalie will have the same momentum. So figure out the mass of the new system:
90.00 kg + 0.16 kg = 90.16 kg
And divide the system momentum by the system mass:
4.8 kg*m/s / 90.16 kg = 0.053238687 m/s
Finally, round to the least precise datum, so the result to 2 significant figures is 0.053 m/s, or 5.3 cm/s.</span>
<span>Subtract the forces in the horizontal direction from the forces in the vertical direction.</span>
Chemical reactions and physical processes
