Answer:
P₁ = 219.3 Pa
Explanation:
This fluid mechanics problem, we can use that the pressure is distributed with the same value throughout the system, which is Pascal's principle.
Let's use the subinidce1 for the small diameter and the subscript 2 for the larger diameter.
P₁ = P₂
pressure is defined by
P = F / A
we subtitute
F₁ / A₁ = F₂ / A₂
F₁ = F₂ A₁ / A₂
the area in a circle is
A = π r² = π d² / 4
we substitute
F₁ = F₂ (d₁ / d₂)²
we calculate
F₁ = 17640 (2/32)²
F₁ = 68.9 N
Having the force to be applied we can find the air pressure on the small plunger
P₁ = F₁ / A₁
P₁ = F₁ 4 / π d₁²
let's calculate
P₁ = 68.9 4 / (π 0.02²)
P₁ = 219.3 Pa
Answer:
2.49 seconds
Explanation:
From the question,
a = (v-u)/t............................ Equation 1
Where a = acceleration, v = final velocity, u = initial velocity, t = time
Make t the subject of the equation
t = (v-u)/a.......................... Equation 2
Given: v = 6.5 m/s, u = 11 m/s, a = -1.81 m/s²
Substitute these values into equation 2
t = (6.5-11)/(-1.81)
t = -4.5/-1.81
t = 2.49 s
Time and velocity are both vectors T/F
Answer:
f = 130 Khz
Explanation:
In a circuit driven by a sinusoidal voltage source, there exists a fixed relationship between the amplitudes of the current and the voltage through any circuit element, at any time.
For an inductor, this relationship can be expressed as follows:
VL = IL * XL (1) , which is a generalized form of Ohm's Law.
XL is called the inductive reactance, and is defined as follows:
XL = ω*L = 2*π*f*L, where f is the frequency of the sinusoidal source (in Hz) and L is the value of the inductance, in H.
Replacing in (1), by the values given of VL, IL, and L, we can solve for f, as follows:
f = VL / 2*π*IL*L = 12 V / 2*π*(3.00*10⁻³) A* (4.9*10⁻³) H = 130 Khz
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