We have that for the Question "Write an expression for the <em>magnitude </em>of charge moved, Q, in terms of N and the fundamental charge e" it can be said its equation is

From the question we are told
Write an expression for the <em>magnitude </em>of charge moved, Q, in terms of N and the fundamental charge e
<h3>An E
xpression for the <em>magnitude </em>of charge moved</h3>
Generally the equation for the <em>magnitude </em>of charge moved, Q is mathematically given as

Therefore
An expression for the <em>magnitude </em>of charge moved, Q, in terms of N and the fundamental charge e" it can be

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This is the same question as the one previously but with more details, so I will just use my previous answer.
1800 to 1820 is 20 minutes.1830 to 1838 is 8 minutes.1840 to 1905 is 25 minutes.
The total time travelled is 20+8+25 = 53 minutes = 3180 seconds.
The distance between Glasgow and Edinburgh is 28 + 12 + 34 = 74 km = 74000 m.
So, the average speed is 74000m/3180s = 23.27 m/s (4 s.f.)
To answer this question, you must remember the equation:
a²+b²= c²
(6.4)² + (12)²= (12.2)²
<span>40.96 + 144 = 184.96
</span> (12.2)² = <span>148.84
</span>
184.96 ≠ 148.84
This cannot be a triangle
hope this helps
Answer:
The equivalent or total resistance of the circuit is 6
Explanation:
6 &6 are in series
6+6=r
r= 12
1/Rtotal= 1/12+1/2
1/Rt=2/12=1/6
Rt=6
Answer:
The speed of the ball is 9.07 m/s.
Explanation:
Given that,
Mass of the lead ball, m = 55 kg
Height of the tower, h = 55 m
We need to find the speed of the ball it has traveled 4.20 m downward, x = 4.2 meters
The initial speed of the ball will be 0 as it was at rest initially. Let v is the speed of the ball after it has traveled 4.20 m downward. It is a case of equation of motion such that :


Here, a = g

v = 9.07 m/s
So, the speed of the ball is 9.07 m/s. Therefore, this is the required solution of given condition.