The direction of this vector is 170° from the positive x-axis.
- Vectors are physical quantities with both magnitude and direction
- To identify the direction, we usually use angles and take a reference axis
- The vector in the diagram is 80° to the left of the positive y-axis, so the direction of the vector is 80° + 90° = 170° anti-clockwise from the positive x-axis.
- Scalars are physical quantities which have only magnitude
- Examples of vector quantities are displacement, velocity, acceleration, force etc
- Examples of scalar quantities are distance, speed, volume, density, mass, time etc
- The direction of the given vector is 170° from the positive x-axis.
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Answer:
Explanation:
A fire alarm notification appliance is an active fire protection component of a fire alarm system. The primary function of the notification appliance is to alert persons at risk.
If want the audible public mode signal to be hear clearly then, we need to have a sound level that is at least 15dB above the average ambient sound level or 5dB above the maximum sound level of at least 1minute
In this case the,
The average ambient sound level is 62dB,
And the maximum sound level is 68dB
Then, the public mode signal should be at least
1. 62dB+ 15dB=77dB
Or
2. 68dB +5dB =73dB.
Then the public mode signal hearing must be at least 77dB.
Given :
The pink car has a velocity of 4.4 m/s to the right while the blue car has a velocity of 6.8 m/s to the left.
To Find :
If the two cars crashed and stuck together, what would their combined momentum be afterwards and what direction would they be moving.
Solution :
Let, combined velocity of the car is v.
Also, let us assume that mass of both the cars are equal and it is m.
By conservation of momentum :
Initial momentum = Final momentum
m( 6.8 ) - m( 4.4 ) = 2mv
2mv =2.4m
v = 1.2 m/s
Therefore, the velocity of combined car after crash is 1.2 m/s .
Answer:
48.22 kg
Explanation:
Applying the law of conservation of momentum,
Total momentum before collision = Total momentum after collision
Note: Since both skaters were initially at rest, then their total momentum before collision is equal to zero.
And the velocity of the second skater will be in opposite direction to the first.
0 = mv+m'v'.................... Equation 1
Where m = mass of the first skater, m' = mass of the second skater, v = final velocity of the first skater, v' = final velocity of the second skater.
make v' the subject of the equation
m' = -mv/v'................. Equation 2
Given: m = 62 kg, v = 0.7 m/s, v' = -0.9 m/s (opposite direction to the first)
Substitute into equation 1
m' = -62(0.7)/-0.9
m' = 48.22 kg
Explanation:
Given that,
The force exerted by the stick on the puck is 975 N
The stick is in contact with the puck for 0.0049 s
Initial speed of the puck, u = 0 (at rest)
(a) We need to find the impulse imparted by the stick to the puck.
Impulse = Force × time
J = 4.7775 kg-m/s
(b) Mass of the puck, m = 1.76 kg
We need to find the speed of the puck just after it leaves the hockey stick.
Let the speed be v.
As impulse is equal to the change in momentum.
So, when the puck leaves the hockey stick its speed is 2.86 m/s.
