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Oduvanchick [21]
3 years ago
5

When this element was discovered, it exhibited luster and malleability, and it reacted very vigorously with water. This element

is never found as a free element in nature and always exists in a compound. To which group does this element most likely belong?
a) alkali metals
b) halogens
c) noble gases
d) transition metals
Chemistry
1 answer:
TEA [102]3 years ago
8 0

Answer:

a) alkali metals

Explanation:

The element described above definitely belonged to the alkali metals, the first group on the periodic table. They show the properties indicated in the text.

  • They are metals because only metals are lustrous and malleable. This eliminates the possibility of them being halogens and noble gases.
  • Only group 1 metals reacts vigorously with water to form alkali.
  • Alkali are aqueous solutions that are basic in nature.
  • The reactivity of group 1 metals is due to their one extra electrons in the outer most shell.
  • These electrons are easily and readily lost in order for such atoms to gain stability and replicate the nearest noble gases.
  • The most reactive metal belongs to this group elements.
  • This is why it is nearly impossible to find them occurring alone in free state.
  • Some of the elements in this group are Li, Na, K, Rb, Cs and Fr.
  • Transition metals have variable oxidation states and some can be found alone in nature.
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Question 12 of 25
NISA [10]

Answer:

B. Equal amounts of all gases have the same volume at the same

conditions

Explanation:

Amedo Avogadro found the relationship between volume of a gas and the number of molecules contained in the volume.

The law states that "equal volumes of all gases at the same temperature and pressure contains equal number of molecules or moles".

The law describes the behavior of gases when involve in chemical reactions. It enables one to change over at will in any statement about gases from volumes to molecules and vice versa.

So, the right option is B which implies that equal amounts of all gases have the same volume at the same conditions.

8 0
3 years ago
What mass of H2O is produced by the combustion of 1.00 mol of CH4?
kkurt [141]
CH4 : H2O
1 : 2

number of moles of H2O = 1.00 x 2
number of moles of H2O = 2.00mol

mass = number of moles x molar mass

mass of H2O = 2.00 x (1 + 1 + 16)
mass of H2O = 36g
8 0
2 years ago
How is primary selection different from secondary succession?
PIT_PIT [208]

Answer:

Explanation:

Primary and secondary succession occur after both human and natural events that cause drastic change in the makeup of an area. Primary succession occurs in areas where there is no soil and secondary succession occurs in areas where there is soil.

In primary succession, newly exposed or newly formed rock is colonized by living things for the first time. In secondary succession, an area previously occupied by living things is disturbed—disrupted—then recolonized following the disturbance.

Hope this helped :)

-<em>Akito</em>

8 0
2 years ago
Calculate the mass of hydrogen in 500 g of Al(C2H3O2)3
Zigmanuir [339]
<span>Answer is: the mass of hydrogen is 22,05 grams.
m(</span>Al(C₂H₃O₂)₃)<span> = 500 g.
M</span>(Al(C₂H₃O₂)₃) = 27 + 6 ·12 + 9 · 1 + 6 · 16 · g/mol = 204 g/mol.<span>
n</span>(Al(C₂H₃O₂)₃) = m(Al(C₂H₃O₂)₃) ÷ M(Al(C₂H₃O₂)₃).
n(Al(C₂H₃O₂)₃) = 500 g ÷ 204 g/mol.
n(Al(C₂H₃O₂)₃) = 2,45 mol.
n(Al(C₂H₃O₂)₃) : n(H) = 1 : 9.
n(H) = 22,05 mol.
m(H) = 22,05 mol · 1 g/mol
m(H) = 22,05 g.

3 0
3 years ago
Read 2 more answers
You have to prepare some 2 M solutions, with 10 g of solute in each. What volume of solution will you prepare, for each solute b
alexdok [17]

Answer:

             0.045 L  or 45 mL

Explanation:

Moles = Mass/M.Mass

Moles = 10 g / 109.94 g/mol

Moles = 0.09 moles

Also,

Molarity = Moles / Vol in L

Or,

Vol in L = Moles / Molarity

Vol in L = 0.09 mol / 2 mol/L

Vol in L = 0.045 L

8 0
2 years ago
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