1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Oduvanchick [21]
2 years ago
5

When this element was discovered, it exhibited luster and malleability, and it reacted very vigorously with water. This element

is never found as a free element in nature and always exists in a compound. To which group does this element most likely belong?
a) alkali metals
b) halogens
c) noble gases
d) transition metals
Chemistry
1 answer:
TEA [102]2 years ago
8 0

Answer:

a) alkali metals

Explanation:

The element described above definitely belonged to the alkali metals, the first group on the periodic table. They show the properties indicated in the text.

  • They are metals because only metals are lustrous and malleable. This eliminates the possibility of them being halogens and noble gases.
  • Only group 1 metals reacts vigorously with water to form alkali.
  • Alkali are aqueous solutions that are basic in nature.
  • The reactivity of group 1 metals is due to their one extra electrons in the outer most shell.
  • These electrons are easily and readily lost in order for such atoms to gain stability and replicate the nearest noble gases.
  • The most reactive metal belongs to this group elements.
  • This is why it is nearly impossible to find them occurring alone in free state.
  • Some of the elements in this group are Li, Na, K, Rb, Cs and Fr.
  • Transition metals have variable oxidation states and some can be found alone in nature.
You might be interested in
What is the density at STP of the gas sulfur hexafluoride, SF6?
svetoff [14.1K]

Answer:

Explanation:

There is a formula for this:

M = DRT/P where M = molar mass. This just derived from PV = nRT where you say n = grams/molar mass. However, just with this formula, we can get D which is density at STP (1 atm and 273K). We find that D = 6.52g/L.

7 0
3 years ago
Read 2 more answers
Which best describes nuclear fission? A nucleus spontaneously splits and absorbs energy. Two nuclei spontaneously combine and ab
Maurinko [17]

Answer:

A nucleus collides with a neutron and splits, releasing energy.

Explanation:

5 0
2 years ago
Read 2 more answers
What is the most likely metal ion present in the fireworks shown in the image?
Tasya [4]
A because of the way it looks and how it works
8 0
3 years ago
Read 2 more answers
A flask contains 6g hydrogen gas and 64 g oxygen at rtp the partial pressure of hydrogen gas in the flask of the total pressure
Alex

Answer:

B.3/5p

Explanation:

For this question, we have to remember <u>"Dalton's Law of Partial Pressures"</u>. This law says that the pressure of the mixture would be equal to the sum of the partial pressure of each gas.

Additionally, we have a <em>proportional relationship between moles and pressure</em>. In other words, more moles indicate more pressure and vice-versa.

P_i=P_t_o_t_a_l*X_i

Where:

P_i=Partial pressure

P_t_o_t_a_l=Total pressure

X_i=mole fraction

With this in mind, we can work with the moles of each compound if we want to analyze the pressure. With the molar mass of each compound we can calculate the moles:

<u>moles of hydrogen gas</u>

The molar mass of hydrogen gas (H_2) is 2 g/mol, so:

6g~H_2\frac{1~mol~H_2}{2~g~H_2}=~3~mol~H_2

<u>moles of oxygen gas</u>

The molar mass of oxygen gas (O_2) is 32 g/mol, so:

64g~H_2\frac{1~mol~H_2}{32~g~H_2}=~2~mol~O_2

Now, total moles are:

Total moles = 2 + 3 = 5

With this value, we can write the partial pressure expression for each gas:

P_H_2=\frac{3}{5}*P_t_o_t_a_l

P_O_2=\frac{2}{5}*P_t_o_t_a_l

So, the answer would be <u>3/5P</u>.

I hope it helps!

5 0
3 years ago
A solution prepared by mixing 10 ml of 1 m hcl and 10 ml of 1.2 m naoh has a ph of
blagie [28]

Answer: pH of resulting solution will be 13

Explanation:

pH is the measure of acidity or alkalinity of a solution.

Moles of H^+ ion = Molarity\times {\text {Volume in L}}=1M\times 0.01L=0.01mol

Moles of OH^- ion = Molarity\times {\text {Volume in L}}=1.2M\times 0.01L=0.012mol

HCl+NaOH\rightarrow NaCl+H_2O

For neutralization:

1 mole of H^+ ion will react with 1 mole of OH^- ion

0.01 mol of H^+  ion will react with =\frac{1}{1}\times 0.01mole of OH^- ion

Thus (0.012-0.01)= 0.002 moles of OH^- are left in 20 ml or 0.02 L of solution.

[OH^-]=\frac{0.002}{0.02L}=0.1M

pOH=-log[OH^-]

pOH=-log[0.1]=1

pH+pOH=14

pH=14-1=13

Thus the pH of resulting solution will be 13

7 0
2 years ago
Other questions:
  • What is the differing between biotic and abiotic
    9·2 answers
  • If a substance goes from the gas phase to the liquid phase, was it heated or cooled
    9·1 answer
  • 25.00 gal/min to L/s, Express your answer using four significant figures.
    5·1 answer
  • Monkeys and bats have similar bone structure in their forelimbs. However, monkeys have longer forelimbs to use for climbing and
    13·1 answer
  • How does the Miller Urey experiment
    7·1 answer
  • What is one way in which sound and light are alike? PLEASE HELP IF YOU WANT BRAINLEIST AND TO HAVE YOUR COMMENT LIKED!!
    14·2 answers
  • WILL GIVE BRAINLIEST!!!
    14·1 answer
  • Which of the following two conditions will favor a spontaneous reaction?
    13·1 answer
  • Which layer is thin, brittle, solid, and composed primarily of silica?
    11·1 answer
  • What is the pH of a 6.50 x 10-2 M NaOH solution?
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!