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sesenic [268]
2 years ago
13

What is the pH of a 6.50 x 10-2 M NaOH solution?

Chemistry
1 answer:
dangina [55]2 years ago
7 0

Answer:

12.82

Explanation:

NaOH is a strong base as it contains an alkali metal (Na). When dealing with strong bases, the concentration of OH- is equal to the concentration of the strong base. So, [OH-] = 6.50 x 10^-2.

Using the concentration of OH-, you can find the pOH, by doing -log[OH-]:

-log(6.50 x 10^-2) = 1.187

Now that you have pOH, you can find pH by doing 14 - 1.187, as pH + pOH = 14.

14 - 1.187 = 12.813

The closest answer to this is option D, 12.82.

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Which statement describes an intensive property of matter? <br>​
Pachacha [2.7K]

Answer:

hope it helped you.

Explanation:

The properties of matter that do not depend on the size or quantity of matter in any way are referred to as an intensive property of matter. Temperatures, density, color, melting and boiling point, etc., all are intensive property as they will not change with a change in size or quantity of matter.

5 0
3 years ago
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What is the mass of calcium in 2.3•10^23 molecules of calcium phosphate
Katena32 [7]

Explanation:

N(Ca)=3×N(Ca₃(PO₄)₂)=

=3×2.3×10²³=6.9×10²³

6.02×10²³→40g

6.9×10²³→Xg

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3 years ago
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Explanation:

6 0
1 year ago
Which matter exists in the gaseous state at room temperature?
Tpy6a [65]
Helium i would think so
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3 years ago
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According to Boyle's law, for a fixed quantity of gas at a given temperature, what quantity relating pressure P and volume V is
yan [13]

<u>Answer:</u> The quantity relating pressure and volume is PV=k and the size of the tank must be 1.92\times 10^3L

<u>Explanation:</u>

To calculate the new volume, we use the equation given by Boyle's law. This law states that pressure is inversely proportional to the volume of the gas at constant temperature.

Mathematically,

P\propto \frac{1}{V}

Or,

PV=k

The equation given by this law is:

P_1V_1=P_2V_2

where,

P_1\text{ and }V_1 are initial pressure and volume.

P_2\text{ and }V_2 are final pressure and volume.

We are given:

P_1=160atm\\V_1=12L\\P_2=1atm\\V_2=?L

Putting values in above equation, we get:

160atm\times 12L=1atm\times V_2\\\\V_2=\frac{160\times 12}{1}=1920L=1.92\times 10^3L

Hence, the size of the tank must be 1.92\times 10^3L

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