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3 years ago

What is the charge on an electrically neutral atom of hydrogen?. . A. 1. . B. 0. . C. +1. . D. +2.

Chemistry

2 answers:

Fynjy0 [20]3 years ago

7 0

Its B zero because its neutral meaning that there balance

harkovskaia [24]3 years ago

6 0

When the number of electron and number of protons are equal in the atom then the atom is said to be an electrically neutral atom. The loss of electron will result in the formation of cation and the atom will possess positive charge which is equal to the number of electrons lost whereas the gain of electron will result in the formation of anion and the atom will possess negative charge which is equal to the number of electrons gained.

The electrically neutral atom have 0 charge as the number of protons and electrons are equal.

For electrically neutral atom of hydrogen, $H$ the number of electron =1 and the number of proton = 1.

Hence, the charge on an electrically neutral atom of hydrogen is 0.

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What mass of calcium chloride is needed to prepare 2.657 L of a 1.56 M solution?

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Answer:

459.126 grams of calcium chloride is needed to prepare 2.657 L of a 1.56 M solution

Explanation:

Molarity is a measure of the concentration of a solute in a solution that indicates the amount of moles of solute that appear dissolved in one liter of the mixture. In other words, molarity is the number of moles of solute that are dissolved in a given volume.

The Molarity of a solution is determined by the following expression:

$Molarity=\frac{number of moles of solute}{volume}$

Molarity is expressed in units $\frac{moles}{liter}$

In this case:

Molarity: 1.56 M= 1.56 $\frac{moles}{liter}$
Number of moles of calcium chlorine= ?
Volume= 2.657 liters

Replacing:

$1.56 M=\frac{Number of moles of calcium chlorine}{2.657 liters}$

Solving:

Number of moles of calcium chlorine= 1.56 M* 2.657 liters

Number of moles of calcium chlorine= 4.14 moles

In other side, you know:

Ca: 40 g/mole
Cl: 35.45 g/mole

Then the molar mass of the calcium chloride CaCl₂ is:

CaCl₂= 40 g/mole + 2* 35.45 g/mole= 110.9 g/mole

Now it is possible to apply the following rule of three: if in 1 mole there is 110.9 g of CaCl₂, in 4.14 moles of the compound how much mass is there?

$mass=\frac{4.14 moles*110.9g}{1 mole}$

mass= 459.126 g

<u><em>459.126 grams of calcium chloride is needed to prepare 2.657 L of a 1.56 M solution</em></u>

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