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3 years ago

What is the charge on an electrically neutral atom of hydrogen?. . A. 1. . B. 0. . C. +1. . D. +2.

Chemistry

2 answers:

Fynjy0 [20]3 years ago

7 0

Its B zero because its neutral meaning that there balance

harkovskaia [24]3 years ago

6 0

When the number of electron and number of protons are equal in the atom then the atom is said to be an electrically neutral atom. The loss of electron will result in the formation of cation and the atom will possess positive charge which is equal to the number of electrons lost whereas the gain of electron will result in the formation of anion and the atom will possess negative charge which is equal to the number of electrons gained.

The electrically neutral atom have 0 charge as the number of protons and electrons are equal.

For electrically neutral atom of hydrogen, $H$ the number of electron =1 and the number of proton = 1.

Hence, the charge on an electrically neutral atom of hydrogen is 0.

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Ammonia will decompose into nitrogen and hydrogen at high temperature. An industrial chemist studying this reaction fills a tank

Masja [62]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The concentration equilibrium constant is $K_c = 14.39$

Explanation:

The chemical equation for this decomposition of ammonia is

$2 NH_3$ ↔ $N_2 + 3 H_2$

The initial concentration of ammonia is mathematically represented a

$[NH_3] = \frac{n_1}{V_1} = \frac{29}{75}$

$[NH_3] = 0.387 \ M$

The initial concentration of nitrogen gas is mathematically represented a

$[N_2] = \frac{n_2}{V_2}$

$[N_2] = 0.173 \ M$

So looking at the equation

Initially (Before reaction)

$NH_3 = 0.387 \ M$

$N_2 = 0 \ M$

$H_2 = 0 \ M$

During reaction(this is gotten from the reaction equation )

$NH_3 = -2 x$ (this implies that it losses two moles of concentration )

$N_2 = + x$ (this implies that it gains 1 moles)

$H_2 = +3 x$ (this implies that it gains 3 moles)

Note : x denotes concentration

At equilibrium

$NH_3 = 0.387 -2x$

$N_2 = x$

$H_2 = 3 x$

Now since

$[NH_3] = 0.387 \ M$

$x= 0.387 \ M$

$H_2 = 3 * 0.173$

$H_2 = 0.519 \ M$

$NH_3 = 0.387 -2(0.173)$

$NH_3 = 0.041 \ M$

Now the equilibrium constant is

$K_c = \frac{[N_2][H_2]^3}{[NH_3]^2}$

substituting values

$K_c = \frac{(0.173) (0.519)^3}{(0.041)^2}$

$K_c = 14.39$

3 0

3 years ago

HELP PLEASE WILL GIVE BRAINLIEST

Crank

Answer:

Option D. Al is above H on the activity series.

Explanation:

The equation for the reaction is given below:

2Al + 6HBr —> 2AlBr₃ + 3H₂

The activity series gives us a background understanding of the reactivity of elements i.e how elements displace other elements when present in solution.

From the activity series of metals, we understood that metal higher in the series will displace those lower in the series.

Considering the equation given above, Al is higher than H in the activity series. Thus, the reaction will proceed as illustrated by the equation.

Therefore, we can conclude that the reaction will only occur if Al is higher than H in the activity series.

4 0

3 years ago

What is 2.15•(6.022•10^23)

sp2606 [1]

Answer:

The answer is 1.29473 x 10^24

Explanation:

6 0

3 years ago

What is the mass of a piece of iron if its density is 1.98 g/mL and its volume is 2.45 mL?

viktelen [127]

Answer:

4.858 g

Explanation:

Start with the formula

density = $\frac{mass}{volume}$

density = 1.98 g/mL

volume = 2.45 mL

mass = ??

rearrange the formula to solve for mass

(density) x (volume) = mass

Add in the substitutes and solve for mass

1.98 g/mL x 2.45 mL = 4.858 g

3 0

3 years ago

A 48.3 mL sample of gas in a cylinder is warmed from 22 °C to

goldenfox [79]

Answer:

58.94 mL

Explanation:

V1 = 48.3 mL V2 = v mL

T1 = 22 degree celsius OR 295 k T2 = 87 degree celsius OR 360 k

We will use the gas equation:

PV = nRT

Since the Pressure (p) , number of moles (n) and the universal gas constant(R) are all constants in this given scenario,

we can say that

V / T = k , (where k is a constant)

Since this is the first case,

V1 / T1 = k --------------------(1)

For case 2:

Since we have the same constants, the equation will be the same

V / T = k (where k is the same constant from before)

V2 / T2 = k (Since this is the second case) ------------------(2)

From (1) and (2):

V1 / T1 = V2 / T2

Now, replacing the variables with the given values

48.3 / 295 = v / 360

v = 48.3*360 / 295

v = 58.94 mL

Therefore, the final volume of the gas is 58.94 mL

4 0

3 years ago