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olga nikolaevna [1]
4 years ago
13

If 6.02×1023 atoms of element Y have a mass of 28.09 g, what is the identity of Y?

Chemistry
1 answer:
Mazyrski [523]4 years ago
8 0

Silicon is the element having a mass of 28.09 g

<u>Explanation</u>:

  • Silicon is the element having an atomic mass of 28.09 g / mol. So 28.09 g of silicon contains 6.023 \times 10^23 atoms. One mole of each element can produce one mole of compound.
  • The Atomic weight of an element can be determined by the number of protons and neutrons present in one atom of that element. So atomic weight expressed in grams always contain the same number of atoms( 6.023 \times10^23).
  • Avagadro number is the number of atoms of 1 mole of any gas at standard temperature and pressure. It has been determined that 6.023 \times 10^23 atoms of an element are equal to the average atomic mass of that element.
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Both covalent-network solids and ionic solids can have melting points well in excess of room temperature, and both can be poor c
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What is the empirical formula for a substance if a 201.6 g sample of it contains 54.0 grams of nitrogen, 15.0 grams of hydrogen,
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The empirical formula of the substance would be  NH_4Cl

<h3>Empirical formula calculation</h3>

The constituents of the compound are as follows:

N = 54/201.6 = 26.78% = 26.78/14 = 1.91 moles

H = 15/201.6 = 7.44% = 7.44/1 = 7.44 moles

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Divide the number of moles by the smallest"

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Thus, the empirical formula is NH_4Cl

More on empirical formula can be found here: brainly.com/question/14044066

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2 years ago
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