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Romashka [77]
3 years ago
14

What is the volume of 0.2 moles of neon gas at STP?

Chemistry
2 answers:
Studentka2010 [4]3 years ago
7 0

Answer: 4.5 L

Explanation: Ideal gas at STP standard temperature and pressure: at STP

P = 1 atm

T = 1 °C convert to K (273 K)

Solution:

PV= nRT

Derive the equation to find V

V= nRT / P

Substitute the values

V= 0.2 moles x 0.082 L.atm/ mol. K x 273 K / 1 atm

Cancel out the units of moles, atm and K so the remaining uni is in L.

eduard3 years ago
4 0

Standard Molar Volume is the volume occupied by one mole of any gas at STP. Remember that "STP" is Standard Temperature and Pressure. Standard temperature is 0 &176:C or 273 K. Standard pressure is 1 atmosphere or 760 mm Hg (also called "torr"). 1 mole of any gas at STP occupies 22.4 liters of volume.

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g 304 mL of a 0.36 M potassium hydroxide solution is added to 341 mL of a 0.51 M lithium hydroxide solution. Calculate the pOH o
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Answer:

<u><em></em></u>

  • <u><em>pOH = 0.36</em></u>

Explanation:

Both <em>potassium hydroxide</em> and <em>lithium hydroxide </em>solutions are strong bases, so you assume 100% dissociation.

<u>1. Potassium hydroxide solution, KOH</u>

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<u>2. LIthium hydroxide, LiOH</u>

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<u />

<u>3. Resulting solution</u>

  • Number of moles of OH⁻ ions = 0.10944 mol + 0.17391 mol = 0.28335 mol

  • Volume of solution = 0.304 liter + 0.341 liter = 0.645 liter

  • Molar concentration = 0.28335 mol / 0.645 liter = 0.4393 M

<u />

<u>4. </u><em><u>pOH</u></em>

      pOH=-\log [OH^-]=-\log (0.439)=0.36   ← answer

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