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Romashka [77]
3 years ago
14

What is the volume of 0.2 moles of neon gas at STP?

Chemistry
2 answers:
Studentka2010 [4]3 years ago
7 0

Answer: 4.5 L

Explanation: Ideal gas at STP standard temperature and pressure: at STP

P = 1 atm

T = 1 °C convert to K (273 K)

Solution:

PV= nRT

Derive the equation to find V

V= nRT / P

Substitute the values

V= 0.2 moles x 0.082 L.atm/ mol. K x 273 K / 1 atm

Cancel out the units of moles, atm and K so the remaining uni is in L.

eduard3 years ago
4 0

Standard Molar Volume is the volume occupied by one mole of any gas at STP. Remember that "STP" is Standard Temperature and Pressure. Standard temperature is 0 &176:C or 273 K. Standard pressure is 1 atmosphere or 760 mm Hg (also called "torr"). 1 mole of any gas at STP occupies 22.4 liters of volume.

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A chef fills a 50ml container with 43.5g of cooking oil. whats the density of the oil
jasenka [17]
I believe the answer is .87g/mL. But I'm not sure so whatevs
4 0
3 years ago
Below are 5 sets of potential solutes for you to compare. Both members of each pair are very soluble in water. If you had equal
Gelneren [198K]

Answer:

Option D. AlCl₃, MgC₂

Explanation:

We need to dissociate all the salts, to determine the i. (Van't Hoff factor).

The salt who has the highest value, will be the better conductor of electricity

CsCl  → Cs⁺  +  Cl⁻   i = 2

CaCl → Ca²⁺ +  Cl⁻   i = 2

CaS → Ca²⁺ +  S⁻²    i = 2

Li₂S → 2Li⁺  +  S⁻²    i = 3

KBr →  K⁺  +  Br⁻       i = 2

AlCl₃ →  Al³⁺ + 3Cl⁻   i = 4

MgC₂  →  Mg²⁺  +  2C⁻   i = 3

KI  →  K⁺  +  I⁻     i = 2

K₂S  →  2K⁺  + S⁻²   i = 3

The biggest i, is in pair D.

6 0
4 years ago
Adding water to a concentrated stock solution results in the...?
SOVA2 [1]

Answer:

The solution becomes diluted.

Explanation:

When you add water to a solution, the number of moles of the solvent stays the same while the volume increases. Therefore, the molarity decreases.

Hope this helps!

5 0
3 years ago
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Answer:

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3 0
2 years ago
If 3.5 grams of NaN3 decomposed, how many grams of N2 would be produced?
Wewaii [24]

Answer:

5.25 moles.

Explanation:

The decomposition reaction of NaN₃ is as follows :

2NaN_3(s)\rightarrow 2Na(s)+3N_2(g)

We need to find how many grams of N₂ produced in the process.

From the above balanced chemical reaction, we conclude that the ratio of moles of sodium azide and nitrogen gas are 2 : 3.

2 moles of sodium azide decomposes to give 3 moles of nitrogen gas. So,

3.5 moles of sodium azide decomposes to give \dfrac{3}{2}\times 3.5=5.25 moles of nitrogen gas.

Hence, the number of moles produced is 5.25 moles.

6 0
3 years ago
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