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photoshop1234 [79]
3 years ago
15

Which one of the following polymer is prepared by condensation polymerization?

Chemistry
2 answers:
nikitadnepr [17]3 years ago
8 0

The answer is Darcon my friend, have a fantastic day

Masteriza [31]3 years ago
3 0

Answer: Dacron

Explanation: It’s obtained by the condensation polymerization of ethylene glycol and dimethylterephthalate.

You might be interested in
A 32 L samples of xenon gas at 10°C is expanded to 35 L. Calculate the final temperature.
morpeh [17]

Answer:

              Final Temperature = 36.54 ⁰C

Explanation:

Lets suppose the gas is acting ideally, then according to Charle's Law, "<em>The volume of a fixed mass of gas at constant pressure is directly proportional to the absolute temperature</em>". Mathematically for initial and final states the relation is as follow,

                                                V₁ / T₁  =  V₂ / T₂

Data Given;

                  V₁  =  32 L

                  T₁  =  10 °C = 283.15 K             ∴ K = °C + 273.15

                  V₂  =  35 L

                  T₂  =  ??

Solving equation for T₂,

                         T₂  =  V₂ × T₁  / V₁

Putting values,

                         T₂  =  (35 L × 283.15 K) ÷ 32 L

                         T₂  =  309.69 K     ∴ ( 36.54 °C )

Result:

           As the volume is increased from 32 L to 35 L, therefore, the temperature must have increased from 10 °C to 36.54 °C.

3 0
3 years ago
How many moles are in 24.75 g of H2O? What is given the conversation and the unknown?
riadik2000 [5.3K]

Answer:

1.373 mol H₂O

General Formulas and Concepts:

<u>Chemistry - Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis

Explanation:

<u>Step 1: Define</u>

24.75 g H₂O

<u>Step 2: Identify Conversions</u>

Molar Mass of H - 1.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of H₂O - 2(1.01) + 16.00 = 18.02 g/mol

<u>Step 3: Convert</u>

<u />24.75 \ g \ H_2O(\frac{1 \ mol \ H_2O}{18.02 \ g \ H_2O} ) = 1.37347 mol H₂O

<u>Step 4: Check</u>

<em>We are given 4 sig figs. Follow sig fig rules and round.</em>

1.37347 mol H₂O ≈ 1.373 mol H₂O

7 0
2 years ago
At a certain temperature this reaction follows second-order kinetics with a rate constant of 14.1·M−1s−1 : →2SO3g+2SO2gO2g Suppo
RoseWind [281]

Answer:

[SO_3]=0.25M

Explanation:

Hello there!

In this case, since the integrated rate law for a second-order reaction is:

[SO_3]=\frac{[SO_3]_0}{1+kt[SO_3]_0}

Thus, we plug in the initial concentration, rate constant and elapsed time to obtain:

[SO_3]=\frac{1.44M}{1+14.1M^{-1}s^{-1}*0.240s*1.44M}\\\\

[SO_3]=0.25M

Best regards!

4 0
2 years ago
Three players (A, B and C) shoot three arrows at a target
UkoKoshka [18]

Answer:

Player B

Explanation:

I just did it and I got it right :)

6 0
3 years ago
Given the balanced equation representing a reaction: 2na(s) + cl2(g) → 2nacl(s) + energy if 46 grams of na and 71 grams of cl2 r
igor_vitrenko [27]
Answer is: 2) 117g.
2Na + Cl₂ → 2NaCl
Step 1: calculate amount of substance of sodium and chlorine.
n(Na) = m(Na)÷M(Na) = 46g ÷ 23 g/mol = 2 mol.
n(Cl₂) = m(Cl₂)÷M(Cl₂) = 71g ÷ 71 g/mol = 1 mol.
Step 2: calculate amount of substance and mass of sodium-chloride.
Because both sodium and chlorine react completely, we can use both n to compare with n of NaCl.
n(Na) : n(NaCl) = 2:2, 2 mol : n(NaCl) = 2:2
n(NaCl) = 2mol, m(NaCl) = 2mol ·5805 g/mol = 117 g.

6 0
3 years ago
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